It doesn't matter whether your path is inertial or not. You age by the
proper time measured along that path.
Brent
On 1/18/2025 4:04 AM, John Clark wrote:
On Fri, Jan 17, 2025 at 7:22 PM Alan Grayson <agrayson2...@gmail.com>
wrote:
/> If you model any observer leaving Earth, that observer cannot
be inertial. AG /
*You can if that observer had always been inertial and had passed the
vicinity of earth at a given "proper time", the time he sees on his
wristwatch. And if X and Y are moving relative to each other they
will each observe that the other's wristwatch is running slower than
their own. If your trajectory is inertial (meaning you're not being
pushed around by external forces) , you will always take the path that
maximizes your proper time between two events.At first that may seem
like a paradox but if you dig a little deeper you realize that it is
not, it's just odd. You really should look at that video I recommended. *
*
*
*Richard Feynman gave a related anecdote in his book "Surely you're
joking Mr. Feynman" when he posed this puzzle to an assistant of
Einstein: *
*"Y/ou blast off in a rocket which has a clock on board, and there's
a clock on the ground. The idea is that you have to be back when
the clock on the ground says one hour has passed. Now you want it so
that/*/*when you come back, your clock is as far ahead as possible.
According to Einstein, if you go very high, your clock will go faster,
because the higher something is in a gravitational field, the faster
its clock goes. But if you try to go too high, since you've only got
an hour, you have to go so fast to get there that the speed slows
yourclock down. So you can't go too high. The question is, exactly
what program of speed and height should you make so that you get the
maximum time on your clock?"*/
/*
*/
/*"This assistant of Einstein worked on it for quite a bit before he
realized that the answer is the real motion of matter. If you shoot
something up in a normal way, so that the time it takes the shell to
go up and come down is an hour, that's the correct motion. It's the
fundamental principle of Einstein's gravity--that is, what's called
the "_proper time_" is at a maximum for the actual curve."*/
*John K Clark See what's on my new list at Extropolis
<https://groups.google.com/g/extropolis>*
um8
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