Try this :
sage: var("x, t") ## t will be used later
(x, t)
sage: y=function("y") ## Note : no default argument
sage: sol=desolve(diff(y(x),x)==(x*y(x)^2 - cos(x)*sin(x) )/(y(x)*(1 - x^2))
,y(x), ics=[0, 2]) ; sol ## Note : specify y argument
1/2*(x^2 - 1)*y(x)^2 + 1/2*cos(x)^2 == (-3/2)
sage:
Thanks so much!
On Wednesday, October 19, 2022 at 7:59:36 PM UTC+5:30 Emmanuel Charpentier
wrote:
> That can be done in Sage in a variety of ways . Here’s one :
>
> var("x, y")
> L = 3# Plotted function
> f =lambda x,y:cos(x)-2*y# Coloring# Colormap
> cm=colormaps["RdBu"]# We have to scale the
That can be done in Sage in a variety of ways . Here’s one :
var("x, y")
L = 3# Plotted function
f =lambda x,y:cos(x)-2*y# Coloring# Colormap
cm=colormaps["RdBu"]# We have to scale the colormap :# Range of values :
possible shortcut via some analytical obviousnesses :# cmin = f(-3, 3).n()#
cma
On Thursday, April 14, 2022 at 9:54:16 AM UTC-4 egourg...@gmail.com wrote:
> Le mercredi 13 avril 2022 à 19:18:48 UTC+2, kcrisman a écrit :
>
>> Eric, if I opened a ticket, would you be willing to add a couple examples
>> of this to the plot documentation?
>
>
> Yes of course.
>
> I wasn't
Le mercredi 13 avril 2022 à 19:18:48 UTC+2, kcrisman a écrit :
> Eric, if I opened a ticket, would you be willing to add a couple examples
> of this to the plot documentation?
Yes of course.
I wasn't aware of this
> but it would be a great addition. (Is there a 3d version as well for
Eric, if I opened a ticket, would you be willing to add a couple examples
of this to the plot documentation? I wasn't aware of this but it would be
a great addition. (Is there a 3d version as well for space curves?)
On Wednesday, April 13, 2022 at 9:12:43 AM UTC-4 egourg...@gmail.com wrote:
>
Hi,
Le vendredi 8 avril 2022 à 22:13:51 UTC+2, fqgo...@colby.edu a écrit :
> There is an easy way to plot vector fields in Sage. Is there an easy way
> to plot a curve and (some of) its tangent vectors?
>
You can achieve this via the method tangent_vector_field() of curves,
see the second pl
Yes, and I should have thought of that!
Fernando
On 3/5/2020 12:13 PM, Dima Pasechnik wrote:
In fact, substituting x and y directly into the equation of the curve
to plot, and clearing denominators,
produces something pretty good,IMHO:
implicit_plot(v^2*3*sqrt(1-u^2-v^2)-u^3*9+u*(1-u^2-v^2),(u
More conceptually, one can use, with care, Sage's substitution facilities:
sage: var('u v x y t');
sage: f=y^2-x^3+x
sage: fs=(f.subs(x=u*3*t^(-1/2),y=v*3*t^(-1/2))*t^(3/2)).expand() #
only works with extra variable t
sage: implicit_plot(fs.subs(t=1-u^2-v^2),(u,-1,1),(v,-1,1))
On Thu, Mar 5, 2020
In fact, substituting x and y directly into the equation of the curve
to plot, and clearing denominators,
produces something pretty good,IMHO:
implicit_plot(v^2*3*sqrt(1-u^2-v^2)-u^3*9+u*(1-u^2-v^2),(u,-1,1),(v,-1,1))
On Thu, Mar 5, 2020 at 4:51 PM Dima Pasechnik wrote:
>
> On Thu, Mar 5, 2020
On Thu, Mar 5, 2020 at 2:32 PM Fernando Gouvea wrote:
>
> This works, in the sense that there's no error. One does get a bunch of
> extraneous points near the boundary of the disk. It's as if plot_points were
> trying to connect the point at (0,1) and the point at (0,-1) along the
> circle, eve
This works, in the sense that there's no error. One does get a bunch of
extraneous points near the boundary of the disk. It's as if plot_points
were trying to connect the point at (0,1) and the point at (0,-1) along
the circle, even though f_uv is 1 on the circle.
Strangely, they occur only on
The easiest way is to use Python functions rather than symbolic ones;
define a function that is 1 outside the unit disk, and implicitly plot it.
sage: def f_uv(u,v):
: if u^2+v^2>=1:
: return 1
: else:
: x=u*sqrt(9/(1-u^2-v^2))
: y=v*sqrt(9/(1-u^
On Wed, Mar 4, 2020 at 12:20 AM Fernando Gouvea wrote:
>
> But no, it doesn't work, since it gives a rectangular plot instead of one in
> polar coordinates. But maybe we are closer.
I looked at the labels on the axes, and they do match the ranges of r
and phi, so I don't udnerstand
how it's poss
But no, it doesn't work, since it gives a rectangular plot instead of
one in polar coordinates. But maybe we are closer.
I still think implicit_plot should be smarter about values that do not
make sense.
Fernando
On 3/3/2020 6:26 PM, Dima Pasechnik wrote:
even better:
sage: var('x y u v r
Nice idea. Thanks.
Fernando
On Tue, Mar 3, 2020 at 6:27 PM Dima Pasechnik wrote:
> even better:
>
> sage: var('x y u v r phi')
> : u=r*cos(phi)
> : v=r*sin(phi)
> : x=u*sqrt(9/(1-r^2))
> : y=v*sqrt(9/(1-r^2))
> : implicit_plot(y^2-x^3+x==0,(r,0,999/1000),(phi,-pi,pi))
>
> On
even better:
sage: var('x y u v r phi')
: u=r*cos(phi)
: v=r*sin(phi)
: x=u*sqrt(9/(1-r^2))
: y=v*sqrt(9/(1-r^2))
: implicit_plot(y^2-x^3+x==0,(r,0,999/1000),(phi,-pi,pi))
On Tue, Mar 3, 2020 at 10:28 PM Dima Pasechnik wrote:
>
> On Tue, Mar 3, 2020 at 10:10 PM Fernando Gouve
On Tue, Mar 3, 2020 at 10:10 PM Fernando Gouvea wrote:
>
> The whole point of this is to show the behavior of the curve near infinity,
> so changing the limits is not an option.
just paste together a number of rectangles where (u,v) stay inside the
unit circle.
(yes, this would need writing a lo
A caveat is that at the boundary, the mapping you describe becomes
non differentiable (the determinant of the differential blows up to
infinity),
so it's going to be painful for implicit_plot to work.
That being said, the following tweak runs ok but it's not ex
The whole point of this is to show the behavior of the curve near
infinity, so changing the limits is not an option.
Fernando
On 3/3/2020 4:15 PM, Dima Pasechnik wrote:
On Tue, Mar 3, 2020 at 8:20 PM Fernando Gouvea wrote:
Here's what I ended up trying, with r=3:
var('x y u v')
x=u*sqrt(9/(
On Tue, Mar 3, 2020 at 9:15 PM Dima Pasechnik wrote:
>
> On Tue, Mar 3, 2020 at 8:20 PM Fernando Gouvea wrote:
> >
> > Here's what I ended up trying, with r=3:
> >
> > var('x y u v')
> > x=u*sqrt(9/(1-u^2-v^2))
> > y=v*sqrt(9/(1-u^2-v^2))
> > implicit_plot(y^2-x^3+x==0,(u,-1,1),(v,-1,1))
> >
> >
On Tue, Mar 3, 2020 at 8:20 PM Fernando Gouvea wrote:
>
> Here's what I ended up trying, with r=3:
>
> var('x y u v')
> x=u*sqrt(9/(1-u^2-v^2))
> y=v*sqrt(9/(1-u^2-v^2))
> implicit_plot(y^2-x^3+x==0,(u,-1,1),(v,-1,1))
>
> That gives an error:
>
> /opt/sagemath-8.9/local/lib/python2.7/site-packages
Here's what I ended up trying, with r=3:
var('x y u v')
x=u*sqrt(9/(1-u^2-v^2))
y=v*sqrt(9/(1-u^2-v^2))
implicit_plot(y^2-x^3+x==0,(u,-1,1),(v,-1,1))
That gives an error:
/opt/sagemath-8.9/local/lib/python2.7/site-packages/sage/ext/interpreters/wrapper_rdf.pyx insage.ext.interpreters.wrapper_r
You can try this to draw the lines between the different points.
The difficulty is to select in your array the points that match together.
import numpy as np
n = 30
array = flatten([[a*vector([float(sqrt(3))/2,0.5]) +
b*vector([float(sqrt(3))/2,-0.5]) for a in (0..n)] for b in (0..n)] +
To draw lines between points P1 and P2 you can use line ([(x1, y1), (x2, y2)]).
But to know which point P1 to join to which point P2 you must:Either build your
points in a logical way to have a method to join them.Or calculate the
distances between all your points (900 points! 900*899/2 dista
Hello,
You have to draw lines between your points.
A solution is to use polyhedron. For instance :
hexa0 = polytopes.regular_polygon(6)
hexa1 = hexa0.translation([float(sqrt(3))/2,1.5])
g = Graphics()
i = 0
while i < 6:
j = 0
while j < 4:
hexa00 = hexa0.translation([i*f
Le vendredi 17 mai 2019 05:35:54 UTC+2, saad khalid a écrit :
>
> Hi everyone:
>
> I'm trying to using Sage's plot functionality to plot the honeycomb
> lattice:
>
> https://sites.google.com/site/makingplots4scipurposes/_/rsrc/1456789513003/gnuplot-samples-of-2d-lattices/honeycomb.png
>
> Plotti
Wed 2018-03-14 13:22:44 UTC, Francesco:
> I have an other question: the command
> plot3d(f, x_range, y_range, viewer="threejs")
> doesn't plot the surface but only the edges of a box. How can i install
this viewer?
What version of Sage are you using?
How did you define f?
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Il giorno venerdì 9 marzo 2018 12:24:50 UTC+1, Francesco ha scritto:
>
> How can i plotting a function of two variables defined in a domain
> different from a square ?
> I need, for example, to plot a f(x,y) where x is between 0 and 1, and y is
> between 0 and x ( it is a triangle )
> Can you
Building on Emmanuel Charpentier's tips, here is an example.
sage: x_range = (0, 1)
sage: y_range = (0, 1)
sage: in_domain = lambda x, y: 0 < y < x < 1
sage: def f(x, y):
: if in_domain(x, y):
: return x^2 + y^2
: return float('nan')
A couple of ideas :
- Parametric plot3d, using a convenient transformation of the parameters
- implicit_plot3d
- list_plot3d
Also, it might help to note that in a 3D plot, points returned as
float("NA") do not plot ; however, this is *undocumented* and I still do
not know how this i
Looks okay to me.
Thanks,
Tom
On Sunday, August 20, 2017 at 7:09:31 PM UTC-5, Andrey Novoseltsev wrote:
>
> On Sunday, 6 August 2017 22:58:20 UTC-6, Andrey Novoseltsev wrote:
>>
>> The next problem is that if a linked cell does not create a new plot,
>> then the old one will be shown again - si
On Sunday, 6 August 2017 22:58:20 UTC-6, Andrey Novoseltsev wrote:
>
> The next problem is that if a linked cell does not create a new plot, then
> the old one will be shown again - since the file is still there.
>
This problem also seems to be solved, please report if you discover any new
issue
Now http://faculty.sfasu.edu/judsontw/math-s304/section-16.html works fine
for me - I don't enforce permission on user files except for group readable
(otherwise the web server will not be able to serve them) and there is a
timestamp added to the name to force browser to load a new version.
The
There is one problem after another... The line I've mentioned earlier
https://github.com/sagemath/sagecell/blob/master/js/session.js#L327
saves and shows the default R plots whose names start with Rplot. This
causes read only permissions on files via
https://github.com/sagemath/sagecell/blob/maste
Yes, I am sure that you have hit on the problem. Let me know what you come
up with.
On Wednesday, July 19, 2017 at 1:23:00 PM UTC+2, Thomas Judson wrote:
>
> The following code works in CoCalc
>
> cases <- c(36, 531, 4233, 8682, 7164, 2229, 600, 164, 57, 722, 1517, 1828,
> 1539, 2416, 3148, 346
On Thursday, 20 July 2017 04:24:50 UTC-6, Thomas Judson wrote:
>
> I am pretty sure that this is an R problem that occurs because of linked
> cells. Look at
> http://faculty.sfasu.edu/judsontw/math-s304/section-16.html. The first
> plot works fine, but somehow I need to clear the previous grap
I am pretty sure that this is an R problem that occurs because of linked
cells. Look
at http://faculty.sfasu.edu/judsontw/math-s304/section-16.html. The first
plot works fine, but somehow I need to clear the previous graphics when I
create a new plot. I have tried dev.off() and graphics.off(
On Wednesday, 19 July 2017 05:23:00 UTC-6, Thomas Judson wrote:
>
> The following code works in CoCalc
>
> cases <- c(36, 531, 4233, 8682, 7164, 2229, 600, 164, 57, 722, 1517, 1828,
> 1539, 2416, 3148, 3465, 1440)
> deaths <- c(0, 0, 130, 552, 738, 414, 198, 90, 56, 50, 71, 137, 178, 194,
> 290,
Thanks Dima!
mandag 26. juni 2017 16.30.20 UTC+2 skrev Dima Pasechnik følgende:
>
> the following works for me:
> sage: var('x y');
> : cmsel = [colormaps['gnuplot2'](i) for i in sxrange(0,1,0.02)]
> : plot3d(lambda
> x,y:((1/(sqrt((2**2)*pi)))*(x+I*y)*exp(-((0.25)*((x+I*y)**2.imag_pa
the following works for me:
sage: var('x y');
: cmsel = [colormaps['gnuplot2'](i) for i in sxrange(0,1,0.02)]
: plot3d(lambda
x,y:((1/(sqrt((2**2)*pi)))*(x+I*y)*exp(-((0.25)*((x+I*y)**2.imag_part(),(x,-3*pi,3*pi),(y,0,2),adaptive=True,
: color=cmsel)
Note that I removed "math." pr
Note, that when brackets are corrected it gives the following result:
TypeError Traceback (most recent call last)
in ()
> 1 plot3d(lambda
x,y:(Integer(1)/(math.sqrt((Integer(2)**Integer(2))*pi)))*(x+I*y)*exp(-((RealNumber('0.25'))*((x+I*y)**Integer(2.imag_
i chime in to +1 for adding a plot attribute to RealSet (as a user, it was
among the 1st things i tried when i discovered this class), something like
`plot(RealSet(-oo, oo))`.
note that matplotlib allows to draw a plain horizontal line:
{{{
from matplotlib import pyplot as plt
plt.figure()
pl
On 12/29/2016 04:46 AM, Fjordforsk A/S wrote:
> Thanks Michael. I am plotting it now, and it is just waiting without giving
> a crash.
> Is it automatically right to use complex_plot command to plot the imaginary
> part of the same plot as given below?
>
It depends, do you expect your function
Thanks Michael. I am plotting it now, and it is just waiting without giving
a crash.
Is it automatically right to use complex_plot command to plot the imaginary
part of the same plot as given below?
onsdag 28. desember 2016 16.58.00 UTC+1 skrev Michael Orlitzky følgende:
>
> On 12/28/2016 10:
On Wednesday, December 28, 2016 at 4:19:55 AM UTC-8, Fjordforsk A/S wrote:
>
> Hello, I am having trouble plotting this function:
>
> sage: *plot3d([(-t+x)^(0.5)*(sech[(t-x)^2]^2)] (x,-5,5), (t, -5, 5))*
>
In python syntax, *sech[(t-x)^2]^2)] *is list indexing, so it will try to
convert the argu
On 12/28/2016 10:33 AM, Fjordforsk A/S wrote:
> This is how its supposed to go:
>
> sage: plot3d(((1 - (3/8 - 3*t^2 - 2*t^4 - 9*x^2 - 10*x^4 - 12*t^2*x^2) +
> i*x*(15/4 + 6*t^2 - 4*t^2 - 2*x^2 - 4*x^4 + 8*t^2*x^2))/(1/8*(3/4 + 9*t^2 +
> 4*t^2+ 16/3*t^6 + 33*x^2 + 36*x^24 + 16/3*x^6)))*e^(i*x)),
This is how its supposed to go:
sage: plot3d(((1 - (3/8 - 3*t^2 - 2*t^4 - 9*x^2 - 10*x^4 - 12*t^2*x^2) +
i*x*(15/4 + 6*t^2 - 4*t^2 - 2*x^2 - 4*x^4 + 8*t^2*x^2))/(1/8*(3/4 + 9*t^2 +
4*t^2+ 16/3*t^6 + 33*x^2 + 36*x^24 + 16/3*x^6)))*e^(i*x)), (x, -2, 2), (t,
-2, 2)
However, Sage thinks that 3*t^
For what it is worth, this works fine in SageMathCloud
https://cloud.sagemath.com/projects/4a5f0542-5873-4eed-a85c-a18c706e8bcd/files/support/2016-10-31-083851%20polyhedron.sagews
which you can easily run locally via Docker:
https://github.com/sagemathinc/smc/blob/master/src/dev/docker/READ
I use Ubuntu 14.04 and Sage 6.8. If i remember correctly I used a binary to
install it.
I indeed tried to upgrade my OS, but i went into some troubles doing it
(not enough remaining space on my disk).
The strange thing is that i asked my colleagues to try with various OS and
Sage version (even
Fri 2016-10-28 17:07:03 UTC+2, marech...@gmail.com:
>
> Hello,
>
> I have troubles plotting 3D polyhedra. I don't understand what happens
> because I've done it for several years and it is the first time it does not
> work.
>
> Small example :
>
> # 2*x + y >= 0 ; -x - y + 2 - z >= 0 ; z >= 0
>
>
> Working for me, just now for cell in worksheet sagemath cloud : I can see
the solid (blue color) for the first plot P.projection().render_solid_3d
Dominique
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syntax should be show(P)
or P
but not print P which gives you your result
Le samedi 17 septembre 2016 23:13:05 UTC+2, Anoz a écrit :
>
> I'm trying to plot the graph ln(1+x/1-x) how do I do this on sagemath , I
> just need the correct syntax.
>
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On mine sage 7.3 it does it straight
Le samedi 17 septembre 2016 23:13:05 UTC+2, Anoz a écrit :
>
> I'm trying to plot the graph ln(1+x/1-x) how do I do this on sagemath , I
> just need the correct syntax.
>
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"sage-sup
Maybe fist write %matplotlib inline
Sometimes I got the same problem
I do it first with python2 kernel and after I do it with sagemath again
Le samedi 17 septembre 2016 23:13:05 UTC+2, Anoz a écrit :
>
> I'm trying to plot the graph ln(1+x/1-x) how do I do this on sagemath , I
> just need the co
On Sun, 18 Sep 2016, jack wrote:
Ubuntu16.04.
P=plot(log((1+x)/(1-x)), (x, -1,1))
show(P)
gives a lengthy error message which ends with
ImportError: cannot import name scimath
I installed sage at /home/jack/Tools
One clue might be the initial message I get on initiating sage in a
terminal.
On Saturday, 17 September 2016 17:13:05 UTC-4, Anoz wrote:
>
> I'm trying to plot the graph ln(1+x/1-x) how do I do this on sagemath , I
> just need the correct syntax.
>
I have just tried this on my newly installed sage7.3 on my new computer
with Ubuntu16.04.
P=plot(log((1+x)/(1-x)), (x, -1,
I did thought of that.
The problem is to determine in advance the right pseudo-value to use in
order not to squash the z values of interest and not to obscure the view of
the surface(s) of interest (plot3d does not have, alas, xmin, ymin zmin,
xmax, ymax, zmax parameters...).
Sincerely,
--
E
2015-12-05 21:03:04 UTC+1, Emmanuel Charpentier:
>
> Plot2d() gracefully handles plotting a fnction undefined (in real terms)
> on part of the plotting domain. For example :
> plot(sqrt(x^2-1),(x,-3/2,3.2))
> displays two half-axes of hyperbole, and waons that some points have been
> lost.
>
>
Of course, there is no such thing as plot2d(). Thinko... Please read plot()
...
Le samedi 5 décembre 2015 21:03:04 UTC+1, Emmanuel Charpentier a écrit :
>
> Plot2d() gracefully handles plotting a fnction undefined (in real terms)
> on part of the plotting domain. For example :
> plot(sqrt(x^2-1),
I see, thank you again! I tried editting bits of your code to see why mine
wasn't working. It seems as though the main difference between our code is
that you "import *" whereas I was doing "import qgamma." When I run my code
with "import *", it works for some reason. Would you happen to know wh
OK .. what you want is :
from mpmath import *
plot(lambda q: qgamma(mpf(0.5),mpf(q)), (0, .99))
print sqrt(pi)
Bonus (my notation Fq is gammaq function and F is gamma function) :
from https://en.wikipedia.org/wiki/Q-gamma_function : lim Fq(x) q->1 =
F(x)
from https://en.wikipedia.org/wiki/G
Just for clarification, how did you know from looking at the line "qgamma(z+
1,q)" that q was supposed to be the first argument given? Because they put
their variable q in second.
Just to double check with wolframalpha, I ran it here:
http://www.wolframalpha.com/input/?i=plot+QGamma%28z%2C.5%29%
Thank you so much for your help! I'm sorry for the lack of clarity, I will
work on that. I really appreciate the help everyone gave, thanks again!
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Explaining better what you want, and you get better help...
..now I understand what you are trying to plot (in 2D, for one specific
value of q)
1) Restart worksheet
2) Copy in cell
from mpmath import *
plot(lambda x: qgamma(mpf(x),mpf(0.5)), (0, .99))
3) Run it => you get your plot
Extra :
from mpmath import qgamma
plot(lambda x: qgamma(.5,x), (x, 0, .99))
That's my code, I ran it again in an entirely new project, and i'm getting
a NoConvergence error. I'm not sure why the error changed between projects,
but there it is.
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I did this code:
from mpmath import *
plot(qgamma((.5,x), (x, 0, .99)))
I'm just trying to get a 2D plot for x =.5, with q going from 0 to .99.
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Trying in the cloud :
1) Code given http://trac.sagemath.org/ticket/19032
var('q,x')
from mpmath import qgamma
plot3d(lambda q,x: qgamma(q,x), (q, 0.5, 3), (x, 2, 10))
=> working fine, using plot3d
2) Your code given previously
var('q,x')
from mpmath import qgamma
plot3d(lambda x: qgamma(.
Hello Chris;
Thank you... you understood me :-)
Sometimes I want to remind what is written on the main "sage-support"...
*Guidelines*: 1. only one question per post | 2. descriptive subject title
| 3. also describe the desired result and the context of the problem.
*Include*: Platform (CPU
Hi Dominique,
Sorry, I didn't intend to not be nice. In putting together the following
example I was able to solve this problem by setting the domain of the
variables to 'real'.
1) Here is a full short example:
var('h','t','px','py','pz','w','R')
P=vector([px,py,pz])
r=vector([R*cos(t*w),
Hello Chris,
Be nice:
1. post a full short example...delta is not defined
2. worksheet in SAGE cloud ? worksheet of your own computer, sagemath local
install ?
Dominique
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Maybe point2d and zip can help?
Could you provide an example
(maybe the example that triggers
the error you quoted)?
Samuel
2015-04-27 04:00:26 UTC+2, Brenton:
> Hi, I started numerical computing in MATLAB and it is the math software I
> am the most familiar with hence why I was wondering if it
I am running Sage 6.6 via VirtualBox, if relevant.
On Monday, 27 April 2015 12:00:26 UTC+10, Brenton wrote:
>
> Hi, I started numerical computing in MATLAB and it is the math software I
> am the most familiar with hence why I was wondering if it is possible to
> plot two column vectors (that ar
I got it. I see that I am not supposed to but limits in the plot
function. The limits of the piecewise function provide that
information.
This works:
f1=x*e^x;
f2=x*e^(-x);
f=Piecewise([[(-5,0),f1],[(0,5),f2]]);
f.plot()
Chris
On Thu, Jul 10, 2014 at 8:42 AM, Chris Maness wrote:
> I am not c
We used something like this for a class once. You can follow which point is
transformed where
def vector_plotter(vec_list, points=False, **kwds):
pic = Graphics()
for c, v in zip(rainbow(len(vec_list), 'rgbtuple'), vec_list):
if points:
pic += point(v, rgbcolor=c, *
On 3/2/14, 9:52, martyall wrote:
I would like to plot the "effects" of an 2 by 2 matrix over the reals
on the unit sphere in the p-norm. By effects I mean I would like to
plot the unit sphere and it's image under a given matrix. In clearest
case when p=2 I found the following code from trac #9728
You have some ways to draw 2D curves in 3 variables f(x,y,z)
1.parametrize curve with two variables u,v with x = x(u,v); y = y(u,v); z =
z(u,v) then f(x,y,z) = F(u,v)
this can be done for many curves
2.use N discrete values for z and plot N curves f1(x,y) = f(x,y,z1), ...,
fN(x,y) = f(x,y,z
Assume A = time, B = frequency and C = intensity.
Doing 2D plot should be possible.
Best regards,
Sami
On Wednesday, 21 October 2009 18:43:54 UTC+3, kcrisman wrote:
>
> Dear Sami,
>
> Unfortunately, your request is somewhat vague. In general, it is not
> possible to visualize the graph of a f
thanks. i'll try it.
On Sunday, September 15, 2013 2:20:45 PM UTC-5, Nils Bruin wrote:
>
>
>
> On Sunday, September 15, 2013 12:12:39 PM UTC-7, Carl Eberhart wrote:
>>
>> I would like to restrict a 3d plot to a certain box in space, say (x,0,1)
>> (y,0,1),(z,.5,1.5)
>> This would be useful in ma
On Sunday, September 15, 2013 12:12:39 PM UTC-7, Carl Eberhart wrote:
>
> I would like to restrict a 3d plot to a certain box in space, say (x,0,1)
> (y,0,1),(z,.5,1.5)
> This would be useful in many situations, say when you want to inspect the
> part of a graph of z=f(x,y)
> where z is betwe
Thanks for the fast reply!
On Tuesday, September 18, 2012 6:24:29 PM UTC+2, Volker Braun wrote:
>
> There is not enough space on your screen to plot non-compact polyhedra, so
> what exactly do you expect as output?
well, the same is true for function plotting but f=3*x; plot(f) gives a
reasona
There is not enough space on your screen to plot non-compact polyhedra, so
what exactly do you expect as output? Right now, the compact part plus
(minkowski sum) the interval (origin, ray generator) is drawn. I guess you
expect the whole half plane clipped by the plot window? How big should the
On 27/04/12 21:55, Jason Grout wrote:
On 4/27/12 2:38 PM, Jose Guzman wrote:
On 27/04/12 20:52, Jason Grout wrote:
On 4/27/12 10:15 AM, Jose Guzman wrote:
Dear colleagues,
I am trying to manipulate an expression that starts at a time =
"tonset". Everything works nice until I try to plot.
#de
On 4/27/12 2:38 PM, Jose Guzman wrote:
On 27/04/12 20:52, Jason Grout wrote:
On 4/27/12 10:15 AM, Jose Guzman wrote:
Dear colleagues,
I am trying to manipulate an expression that starts at a time =
"tonset". Everything works nice until I try to plot.
#define independent variable
sage: t = var
On 27/04/12 20:52, Jason Grout wrote:
On 4/27/12 10:15 AM, Jose Guzman wrote:
Dear colleagues,
I am trying to manipulate an expression that starts at a time =
"tonset". Everything works nice until I try to plot.
#define independent variable
sage: t = var('t')
# define parameters
sage: taum, t
On 4/27/12 10:15 AM, Jose Guzman wrote:
Dear colleagues,
I am trying to manipulate an expression that starts at a time =
"tonset". Everything works nice until I try to plot.
#define independent variable
sage: t = var('t')
# define parameters
sage: taum, tauh = var('taum, tauh')
sage: tonset=va
Yes, exactly!
Thank you Jason:
Th
- Original Message -
From: Jason Grout
To: sage-support@googlegroups.com
Sent: Thu, 23 Feb 2012 10:46:44 -0600
Subject: [sage-support] Re: Plotting untouched linear system
On 2/23/12 10:30 AM, btho...@nexus.hu wrote:
> Hello,
>
> For clarit
On 2/23/12 10:30 AM, btho...@nexus.hu wrote:
Hello,
For clarity reasons, in notebook, im trying to print a system before any
symbolic manipulation:
A=matrix(3,3,[x0,y0,1,x1,y1,1,x2,y2,1])
unk= vector(3,[a,b,c])
rhs=vector(3,[w0,w1,w2])
I would like to print A*unk=rhs such that the output becom
On Dec 9, 5:47 pm, "D. S. McNeil" wrote:
> > Hi all, I'm confused why this code results in a graph plotted with the
> > (single) edges labeled with the weight between each pair of vertices:
>
> > M = Matrix([[0,1,-1,5],[1,0,-1/2,-1],[-1,-1/2,0,2],[5,-1,2,0]])
> > G = Graph(M,sparse=True)
> > G.plo
On 10/3/11 5:21 AM, Vince wrote:
Hi all,
I've been attempting to plot some data from a CSV file (two columns)
in SAGE and I've completely failed. Is there a nice tutorial on line
somewhere? If not could anyone perhaps point me to a good starting
point (I've been unable to import the data in to S
You can use one of the ODE solvers...
--
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On 5/7/11 5:00 PM, ObsessiveMathsFreak wrote:
I still can't get this code to work.
In lieu of any external solutions, I've tried to hack something
together in sage itself, using the standard 3d functionality.
Basically it involves drawing a series of implicit plot 3d countours,
then cutting into
that
> you are not quite familiar to mayavi,
> I'm sending a code I modify to plot an interpolation of Mexico's City (data
> points file included) , and some nice pictures I got with mayavi.
>
> Regards,
> Jorge
>
>
>
>
>
>
>
> > Date: Fri
Python parafernalia, I have been
> > since then working with it inside sage,
> > without any problem.
>
> > Regards
> > Jorge
>
> > > Date: Thu, 5 May 2011 12:40:55 -0700
> > > Subject: [sage-support] Re: Plotting Functions of 3 variables
> >
king with it inside sage,
> without any problem.
>
> Regards
> Jorge
>
>
>
>
>
>
>
> > Date: Thu, 5 May 2011 12:40:55 -0700
> > Subject: [sage-support] Re: Plotting Functions of 3 variables
> > From: obsessivemathsfr...@gmail.com
> > To: sage
u, 5 May 2011 12:40:55 -0700
> Subject: [sage-support] Re: Plotting Functions of 3 variables
> From: obsessivemathsfr...@gmail.com
> To: sage-support@googlegroups.com
>
> _None_ of those experimental packages work on my system. The first
> dependancy, wxPython-2.8.7.1.spkg give
_None_ of those experimental packages work on my system. The first
dependancy, wxPython-2.8.7.1.spkg give the following error (after
taking ages compiling)
In file included from ../src/gtk/gsockgtk.cpp:21:
../include/wx/gsocket.h:40: error: using typedef-name ‘GSocket’ after
‘class’
/usr/include/g
On May 5, 1:43 pm, ObsessiveMathsFreak
wrote:
> Thanks but, these methods are not wholly adequate for my purposes.
>
> I have been investigating the mayavi python package and the examples
> given
> herehttp://code.enthought.com/projects/mayavi/docs/development/html/mayav...
>
> Apparently sagem
> > > I currently have a function of three variables w=f(x,y,z), which I
> > > would like to plot in 3D if possible (e.g. via coloured plots)
Not sure about color, but `implicit_plot3d` can produce 3D contour
plots.
http://www.sagemath.org/doc/reference/sage/plot/plot3d/implicit_plot3d.html
> >
Thanks but, these methods are not wholly adequate for my purposes.
I have been investigating the mayavi python package and the examples
given here
http://code.enthought.com/projects/mayavi/docs/development/html/mayavi/mlab_case_studies.html#mlab-case-studies
Apparently sagemath has support for ma
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