Re: [obm-l] limites

[Oswaldo Stanziola]

Oi Claudio.   Agradecido pela aten��o. ----- Original Message ----- From: Cl�udio (Pr�tica) To: [EMAIL PROTECTED] Sent: Wednesday, April 02, 2003 12:48 PM Subject: Re: [obm-l] limites f(x) = (sen(x)/cos(x) - x)/(x - sen(x)) = (sen(x) - x*cos(x))/[cos(x)*(x - sen(x))] = = [(sen(x)/x) - cos(x)] / [cos(x)*(1 - sen(x)/x)]   Usando os primeiros dois termos das s�ries de Taylor de seno e cosseno, teremos:   sen(x)/x = 1 - x^2/6 + O(x^4)   e   cos(x) = 1 - x^2/2 + O(x^4)   Assim: f(x) = [x^2/2 - x^2/6 + O(x^4)] / [(1 - x^2/2 + O(x^4))*(x^2/6 + O(x^4))]   = [1/2 - 1/6 + O(x^4)/x^2] / [1/6 + O(x^4)/x^2]   Logo, quando x -> 0, f(x) -> (1/2 - 1/6)/(1/6) = 2.   Um abra�o, Claudio.    ----- Original Message ----- From: Oswaldo Stanziola To: [EMAIL PROTECTED] Sent: Wednesday, April 02, 2003 11:32 AM Subject: [obm-l] limites Olah pessoal,   Agradeceria muito pela ajuda na resoluc�o do exercicio: Sendo f(x) = ( tg x - x)/( x - sen x) entao f(x) eh:                                                          x->0 Resp.: 2   Obrigado. Oswaldo [EMAIL PROTECTED]