On Wed, 7 May 2025 17:32:06 GMT, Raffaello Giulietti <rgiulie...@openjdk.org> wrote:
> Ah right, but you probably want No, the sufficient condition to get the overflow is `(bitLength() - 1L) * exponent + 1L > Integer.MAX_VALUE`, which is equivalent to that one I wrote above. ------------- PR Review Comment: https://git.openjdk.org/jdk/pull/24690#discussion_r2078142049
