Clearly the answer is a program that runs every snippet posted to this
mailing list through kibit (https://github.com/jonase/kibit).

On Tue, Feb 17, 2015 at 1:49 PM, Colin Yates <colin.ya...@gmail.com> wrote:

> Style police would point out zero? and when-not :).
> On 17 Feb 2015 20:40, "Cecil Westerhof" <cldwester...@gmail.com> wrote:
>
>> 2015-02-17 20:26 GMT+01:00 Timothy Baldridge <tbaldri...@gmail.com>:
>>
>>> Tweak as needed:
>>>
>>> (keep-indexed
>>>               (fn [i v]
>>>                 (if (= 0 (mod i 5))
>>>                   nil
>>>                   v))
>>>               (range 30))
>>>
>>
>> ​I made the following:
>> ​
>>
>> ​    (defn indexed-sieve [index this-list]
>>       (keep-indexed
>>         (fn [i v]
>>           (if (= 0 (mod (inc i) index))
>>               nil
>>             v))
>>         this-list))
>>
>> The first element should not be filtered (counting from 1) and because I
>> will use it more often I created a function.​
>>
>>
>>
>>> On Tue, Feb 17, 2015 at 12:21 PM, Cecil Westerhof <
>>> cldwester...@gmail.com> wrote:
>>>
>>>> What is the best way to remove all elements which position (counting
>>>> from 1) is a multiply of five out of a list?
>>>>
>>>> So the list:
>>>>     (1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21)
>>>> ​becomes:
>>>>     (1 2 3 4 6 7 8 9 11 12 13 14 16 17 18 19 21)​
>>>>
>>>
>> --
>> Cecil Westerhof
>>
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-- 
“One of the main causes of the fall of the Roman Empire was that–lacking
zero–they had no way to indicate successful termination of their C
programs.”
(Robert Firth)

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