Tweak as needed:
(keep-indexed
(fn [i v]
(if (= 0 (mod i 5))
nil
v))
(range 30))
On Tue, Feb 17, 2015 at 12:21 PM, Cecil Westerhof <cldwester...@gmail.com>
wrote:
> What is the best way to remove all elements which position (counting from
> 1) is a multiply of five out of a list?
>
> So the list:
> (1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21)
> becomes:
> (1 2 3 4 6 7 8 9 11 12 13 14 16 17 18 19 21)
>
> --
> Cecil Westerhof
>
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