this works => (filter #(not= (mod % 5) 0) (range 22)) (1 2 3 4 6 7 8 9 11 12 13 14 16 17 18 19 21)
On Tuesday, February 17, 2015 at 2:21:20 PM UTC-5, Cecil Westerhof wrote: > > What is the best way to remove all elements which position (counting from > 1) is a multiply of five out of a list? > > So the list: > (1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21) > becomes: > (1 2 3 4 6 7 8 9 11 12 13 14 16 17 18 19 21) > > -- > Cecil Westerhof > -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en --- You received this message because you are subscribed to the Google Groups "Clojure" group. To unsubscribe from this group and stop receiving emails from it, send an email to clojure+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
