True, that works, but he wants to remove based on element position, not
element value.

Timothy

On Tue, Feb 17, 2015 at 12:28 PM, Ivan L <ivan.laza...@gmail.com> wrote:

> this works
>
> => (filter #(not= (mod % 5) 0) (range 22))
> (1 2 3 4 6 7 8 9 11 12 13 14 16 17 18 19 21)
>
>
> On Tuesday, February 17, 2015 at 2:21:20 PM UTC-5, Cecil Westerhof wrote:
>>
>> What is the best way to remove all elements which position (counting from
>> 1) is a multiply of five out of a list?
>>
>> So the list:
>>     (1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21)
>> ​becomes:
>>     (1 2 3 4 6 7 8 9 11 12 13 14 16 17 18 19 21)​
>>
>> --
>> Cecil Westerhof
>>
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