Hello Elias, yes now it's working fine.
thanks, Fausto 2015-04-14 15:40 GMT+02:00 Elias Mårtenson <loke...@gmail.com>: > OK, I believe I have fixed it. Please check the latest version in git. > > Regards, > Elias > > On 14 April 2015 at 19:38, Fausto Saporito <fausto.sapor...@gmail.com> > wrote: > >> Hello Jay, >> >> I'm using emacs and gnu-apl-mode but when I try to define the operator >> without the space I receive an error: "unable to parse". >> >> Generally I use emacs, cause under Mac OS X I'm not able to use the APL >> keyboard... I didn't find a way :-) (tried xmodmap, setxbdmap, etc). >> >> I also tried with ]keyb (it displays correctly the APL keyboard on the >> screen, but I don't understand how the keys are mapped). >> >> I tested without emacs (using copy'n'paste) and it works. >> >> regards, >> Fausto >> >> >> 2015-04-14 13:25 GMT+02:00 Jay Foad <jay.f...@gmail.com>: >> >>> You shouldn't need a space after the right parenthesis. >>> >>> This works for me: >>> >>> z←(F scan)x;y >>> z←⊂y←↑x >>> ∆1:→(0=⍴x←1↓x)/0 >>> z←z,⊂y←y F↑x >>> →∆1 >>> >>> +scan 2 3 4 >>> 2 5 9 >>> >>> I had to: >>> - change " to ↓ for Drop >>> - use monadic ↑ instead of ⊃ for First (this is a Dyalog "migration >>> level" thing) >>> - replace modified assignment z,← with z←z, >>> >>> Jay. >>> >>> On 14 April 2015 at 12:06, Fausto Saporito <fausto.sapor...@gmail.com> >>> wrote: >>> > Hi Jürgen, >>> > >>> > thanks... my fault. I wrote without space after the right parenthesis >>> and >>> > the interpret gave me an error. I.e. ∇z←(F scan)x;y >>> > >>> > I didn't notice the blank space was mandatory. >>> > >>> > regards, >>> > Fausto >>> > >>> > >>> > >>> > 2015-04-14 12:58 GMT+02:00 Juergen Sauermann >>> > <juergen.sauerm...@t-online.de>: >>> >> >>> >> Hi Fausto, >>> >> >>> >> page 30 (Defined Functions and Operators) explains it. >>> >> In your example below F is expected to be a function because it >>> >> is inside () in the header while the variable(s) are outside (). >>> >> >>> >> /// Jürgen >>> >> >>> >> >>> >> On 04/14/2015 12:42 PM, Fausto Saporito wrote: >>> >> >>> >> Hello all, >>> >> >>> >> sorry if I bother you again, but I tried to find some hints in the >>> APL2 >>> >> Language Reference Manual without luck. >>> >> >>> >> In the Sullivan's paper, there's the reference to a "scan" operator >>> quite >>> >> fast more suited to be used with his multi precision package. >>> >> This is its definition: >>> >> >>> >> ∇ z←(F scan)x;y >>> >> >>> >> z←⊂y←⊃x >>> >> ∆1:!(0=⍴x←1"x)/0 >>> >> z,←⊂y←y F⊃x >>> >> !∆1 >>> >> >>> >> the "!" is the branch arrow. >>> >> >>> >> Now the problem is with GNU APL I cannot define this operator, cause I >>> >> don't know how to specify F is a function not a variable. >>> >> >>> >> is there a way to do that ? >>> >> >>> >> thanks, >>> >> fausto >>> >> >>> >> >>> >> >>> >> >>> > >>> >> >> >
