Hello Jay,

I'm using emacs and gnu-apl-mode but when I try to define the operator
without the space I receive an error: "unable to parse".

Generally I use emacs, cause under Mac OS X I'm not able to use the APL
keyboard... I didn't find a way :-) (tried xmodmap, setxbdmap, etc).

I also tried with ]keyb (it displays correctly the APL keyboard on the
screen, but I don't understand how the keys are mapped).

I tested without emacs (using copy'n'paste) and it works.

regards,
Fausto


2015-04-14 13:25 GMT+02:00 Jay Foad <jay.f...@gmail.com>:

> You shouldn't need a space after the right parenthesis.
>
> This works for me:
>
> z←(F scan)x;y
> z←⊂y←↑x
> ∆1:→(0=⍴x←1↓x)/0
> z←z,⊂y←y F↑x
> →∆1
>
>       +scan 2 3 4
> 2 5 9
>
> I had to:
> - change " to ↓ for Drop
> - use monadic ↑ instead of ⊃ for First (this is a Dyalog "migration
> level" thing)
> - replace modified assignment z,← with z←z,
>
> Jay.
>
> On 14 April 2015 at 12:06, Fausto Saporito <fausto.sapor...@gmail.com>
> wrote:
> > Hi Jürgen,
> >
> > thanks... my fault. I wrote without space after the right parenthesis and
> > the interpret gave me an error. I.e. ∇z←(F scan)x;y
> >
> > I didn't notice the blank space was mandatory.
> >
> > regards,
> > Fausto
> >
> >
> >
> > 2015-04-14 12:58 GMT+02:00 Juergen Sauermann
> > <juergen.sauerm...@t-online.de>:
> >>
> >> Hi Fausto,
> >>
> >> page 30 (Defined Functions and Operators) explains it.
> >> In your example below F is expected to be a function because it
> >> is inside () in the header while the variable(s) are outside ().
> >>
> >> /// Jürgen
> >>
> >>
> >> On 04/14/2015 12:42 PM, Fausto Saporito wrote:
> >>
> >> Hello all,
> >>
> >> sorry if I bother you again, but I tried to find some hints in the APL2
> >> Language Reference Manual without luck.
> >>
> >> In the Sullivan's paper, there's the reference to a "scan" operator
> quite
> >> fast more suited to be used with his multi precision package.
> >> This is its definition:
> >>
> >> ∇ z←(F scan)x;y
> >>
> >> z←⊂y←⊃x
> >> ∆1:!(0=⍴x←1"x)/0
> >> z,←⊂y←y F⊃x
> >> !∆1
> >>
> >> the "!" is the branch arrow.
> >>
> >> Now the problem is with GNU APL I cannot define this operator, cause I
> >> don't know how to specify F is a function not a variable.
> >>
> >> is there a way to do that ?
> >>
> >> thanks,
> >> fausto
> >>
> >>
> >>
> >>
> >
>

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