That's probably a bug in the parsing on the Emacs side. I'll check it when I get back home tonight. On 14 Apr 2015 19:39, "Fausto Saporito" <fausto.sapor...@gmail.com> wrote:
> Hello Jay, > > I'm using emacs and gnu-apl-mode but when I try to define the operator > without the space I receive an error: "unable to parse". > > Generally I use emacs, cause under Mac OS X I'm not able to use the APL > keyboard... I didn't find a way :-) (tried xmodmap, setxbdmap, etc). > > I also tried with ]keyb (it displays correctly the APL keyboard on the > screen, but I don't understand how the keys are mapped). > > I tested without emacs (using copy'n'paste) and it works. > > regards, > Fausto > > > 2015-04-14 13:25 GMT+02:00 Jay Foad <jay.f...@gmail.com>: > >> You shouldn't need a space after the right parenthesis. >> >> This works for me: >> >> z←(F scan)x;y >> z←⊂y←↑x >> ∆1:→(0=⍴x←1↓x)/0 >> z←z,⊂y←y F↑x >> →∆1 >> >> +scan 2 3 4 >> 2 5 9 >> >> I had to: >> - change " to ↓ for Drop >> - use monadic ↑ instead of ⊃ for First (this is a Dyalog "migration >> level" thing) >> - replace modified assignment z,← with z←z, >> >> Jay. >> >> On 14 April 2015 at 12:06, Fausto Saporito <fausto.sapor...@gmail.com> >> wrote: >> > Hi Jürgen, >> > >> > thanks... my fault. I wrote without space after the right parenthesis >> and >> > the interpret gave me an error. I.e. ∇z←(F scan)x;y >> > >> > I didn't notice the blank space was mandatory. >> > >> > regards, >> > Fausto >> > >> > >> > >> > 2015-04-14 12:58 GMT+02:00 Juergen Sauermann >> > <juergen.sauerm...@t-online.de>: >> >> >> >> Hi Fausto, >> >> >> >> page 30 (Defined Functions and Operators) explains it. >> >> In your example below F is expected to be a function because it >> >> is inside () in the header while the variable(s) are outside (). >> >> >> >> /// Jürgen >> >> >> >> >> >> On 04/14/2015 12:42 PM, Fausto Saporito wrote: >> >> >> >> Hello all, >> >> >> >> sorry if I bother you again, but I tried to find some hints in the APL2 >> >> Language Reference Manual without luck. >> >> >> >> In the Sullivan's paper, there's the reference to a "scan" operator >> quite >> >> fast more suited to be used with his multi precision package. >> >> This is its definition: >> >> >> >> ∇ z←(F scan)x;y >> >> >> >> z←⊂y←⊃x >> >> ∆1:!(0=⍴x←1"x)/0 >> >> z,←⊂y←y F⊃x >> >> !∆1 >> >> >> >> the "!" is the branch arrow. >> >> >> >> Now the problem is with GNU APL I cannot define this operator, cause I >> >> don't know how to specify F is a function not a variable. >> >> >> >> is there a way to do that ? >> >> >> >> thanks, >> >> fausto >> >> >> >> >> >> >> >> >> > >> > >
