Hi Jürgen, thanks... my fault. I wrote without space after the right parenthesis and the interpret gave me an error. I.e. ∇z←(F scan)x;y
I didn't notice the blank space was mandatory. regards, Fausto 2015-04-14 12:58 GMT+02:00 Juergen Sauermann <juergen.sauerm...@t-online.de> : > Hi Fausto, > > page 30 (Defined Functions and Operators) explains it. > In your example below F is expected to be a function because it > is inside () in the header while the variable(s) are outside (). > > /// Jürgen > > > On 04/14/2015 12:42 PM, Fausto Saporito wrote: > > Hello all, > > sorry if I bother you again, but I tried to find some hints in the APL2 > Language Reference Manual without luck. > > In the Sullivan's paper, there's the reference to a "scan" operator quite > fast more suited to be used with his multi precision package. > This is its definition: > > ∇ z←(F scan)x;y > > z←⊂y←⊃x > ∆1:!(0=⍴x←1"x)/0 > z,←⊂y←y F⊃x > !∆1 > > the "!" is the branch arrow. > > Now the problem is with GNU APL I cannot define this operator, cause I > don't know how to specify F is a function not a variable. > > is there a way to do that ? > > thanks, > fausto > > > > >
