Hi Elias,

thanks a lot.
It should be possible to add also the line numbers when I edit a function
with emacs ?

thanks,
fausto


2015-04-14 13:41 GMT+02:00 Elias Mårtenson <loke...@gmail.com>:

> That's probably a bug in the parsing on the Emacs side. I'll check it when
> I get back home tonight.
> On 14 Apr 2015 19:39, "Fausto Saporito" <fausto.sapor...@gmail.com> wrote:
>
>> Hello Jay,
>>
>> I'm using emacs and gnu-apl-mode but when I try to define the operator
>> without the space I receive an error: "unable to parse".
>>
>> Generally I use emacs, cause under Mac OS X I'm not able to use the APL
>> keyboard... I didn't find a way :-) (tried xmodmap, setxbdmap, etc).
>>
>> I also tried with ]keyb (it displays correctly the APL keyboard on the
>> screen, but I don't understand how the keys are mapped).
>>
>> I tested without emacs (using copy'n'paste) and it works.
>>
>> regards,
>> Fausto
>>
>>
>> 2015-04-14 13:25 GMT+02:00 Jay Foad <jay.f...@gmail.com>:
>>
>>> You shouldn't need a space after the right parenthesis.
>>>
>>> This works for me:
>>>
>>> z←(F scan)x;y
>>> z←⊂y←↑x
>>> ∆1:→(0=⍴x←1↓x)/0
>>> z←z,⊂y←y F↑x
>>> →∆1
>>>
>>>       +scan 2 3 4
>>> 2 5 9
>>>
>>> I had to:
>>> - change " to ↓ for Drop
>>> - use monadic ↑ instead of ⊃ for First (this is a Dyalog "migration
>>> level" thing)
>>> - replace modified assignment z,← with z←z,
>>>
>>> Jay.
>>>
>>> On 14 April 2015 at 12:06, Fausto Saporito <fausto.sapor...@gmail.com>
>>> wrote:
>>> > Hi Jürgen,
>>> >
>>> > thanks... my fault. I wrote without space after the right parenthesis
>>> and
>>> > the interpret gave me an error. I.e. ∇z←(F scan)x;y
>>> >
>>> > I didn't notice the blank space was mandatory.
>>> >
>>> > regards,
>>> > Fausto
>>> >
>>> >
>>> >
>>> > 2015-04-14 12:58 GMT+02:00 Juergen Sauermann
>>> > <juergen.sauerm...@t-online.de>:
>>> >>
>>> >> Hi Fausto,
>>> >>
>>> >> page 30 (Defined Functions and Operators) explains it.
>>> >> In your example below F is expected to be a function because it
>>> >> is inside () in the header while the variable(s) are outside ().
>>> >>
>>> >> /// Jürgen
>>> >>
>>> >>
>>> >> On 04/14/2015 12:42 PM, Fausto Saporito wrote:
>>> >>
>>> >> Hello all,
>>> >>
>>> >> sorry if I bother you again, but I tried to find some hints in the
>>> APL2
>>> >> Language Reference Manual without luck.
>>> >>
>>> >> In the Sullivan's paper, there's the reference to a "scan" operator
>>> quite
>>> >> fast more suited to be used with his multi precision package.
>>> >> This is its definition:
>>> >>
>>> >> ∇ z←(F scan)x;y
>>> >>
>>> >> z←⊂y←⊃x
>>> >> ∆1:!(0=⍴x←1"x)/0
>>> >> z,←⊂y←y F⊃x
>>> >> !∆1
>>> >>
>>> >> the "!" is the branch arrow.
>>> >>
>>> >> Now the problem is with GNU APL I cannot define this operator, cause I
>>> >> don't know how to specify F is a function not a variable.
>>> >>
>>> >> is there a way to do that ?
>>> >>
>>> >> thanks,
>>> >> fausto
>>> >>
>>> >>
>>> >>
>>> >>
>>> >
>>>
>>
>>

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