I know that simple line plots showing a point representing the mean + an
error bar are difficult in R, but I am clearly missing something. I simply
want to show how a the mean and 95% CI of a chemical concentration (y) vary
over space (x) under four temperature regimes (T; a categorical factor).
> Any and all help is deeply appreciated.
If you do not want to learn all the inns and outs of Emacs, just download
the Emacs distribution provided by Vincent Goulet - it has ESS. Uninstall
your present Emacs, go to http://vgoulet.act.ulaval.ca/en/ressources/emacs/
download Vincent's distributi
Hello All,
I want to draw a figure with filled contour in a irregular map.
But I found that the contours overlap the boundaries of the map, and also some
regions in the map were not filled.
I have following data:
data1. A shapefile (i.e., a map with boundary, for example, the whole Australia
Yes, that was the original question: when a variable in a data frame is
a matrix instead of an ordinary variable merge() handles the missing
cases so that only the first column of the matrix gets NA and the rest
are recycled. If the matrix is broken to several variables everything
works fine.
Why
I am looking for information on experimentation with the use
of R in the teaching of statistics and science in schools. Any
leads would be very welcome. I am certain that there is such
experimentation.
I've made this inquiry on r-sig-teaching, with no response.
John.
John Maindonald
Hi Dirk,
Thank you for your prompt reply. The issue has been actually resolved in just
a few hours after I posted it. Many apologies for being too impatient!
Best,
Ivan
On Thursday 17 September 2009 10:15:04 pm Dirk Eddelbuettel wrote:
> Ivan,
>
> On 17 September 2009 at 21:22, Ivan Adzhubey w
On 18 September 2009 at 17:11, Don MacQueen wrote:
| I'd suggest using Rprof to find out where the cpu time is being
| spent.
Seconded. Profiling should help you.
Some other ideas:
-- look at the data.table package (on CRAN) by Matt Dowle which he
uses as a fast lookup 'database alternativ
On Fri, Sep 18, 2009 at 8:11 PM, Don MacQueen wrote:
> I wouldn't assume R is making a copy; it depends on what you're doing with
> the dataframe.
Indeed ... I thought R had copy-on-write semantics for function
arguments, no? If so, then if your function doesn't change the
elements in the matrix/
I wouldn't assume R is making a copy; it depends on what you're doing
with the dataframe.
I'd suggest using Rprof to find out where the cpu time is being
spent. If you can adapt your problem to use all numbers or all
characters then you can store the data in a matrix instead of a data
frame,
On Sep 18, 2009, at 7:38 PM, Mark Knecht wrote:
Hi,
Is there a way to pass the address of a data.frame through a set of
functions in R? I've got some code which is slowing down I think
because my data.frames are getting much larger - now approaching 1
million rows by 50-100 columns - and my f
You can use R environments or proto objects from the proto package
(http://r-proto.googlecode.com) which are environments with additional
oo support using the prototype model) or the oo.R package which is similar
but uses a more conventional oo model.
On Fri, Sep 18, 2009 at 7:38 PM, Mark Knecht
Hi,
Is there a way to pass the address of a data.frame through a set of
functions in R? I've got some code which is slowing down I think
because my data.frames are getting much larger - now approaching 1
million rows by 50-100 columns - and my functions - originally written
for much smaller data
And if you make 'year' a factor with levels '2007' and '2008'
you'll get your second wish.
Peter
Sundar Dorai-Raj wrote:
I think this ought to work for you:
library(lattice)
set.seed(42)
d <- data.frame(year = c(rep(2007,12), rep(2008,12)),
treatment = rep(LETTERS[1:3], each =
I think this ought to work for you:
library(lattice)
set.seed(42)
d <- data.frame(year = c(rep(2007,12), rep(2008,12)),
treatment = rep(LETTERS[1:3], each = 4, times = 2))
d$cover <- rnorm(nrow(d))
d$variable <- rnorm(nrow(d))
xyplot(variable ~ cover | year, d,
panel = fun
?aggregate
with(xx,aggregate(var2, list(var1=var1),sum)
--- On Fri, 9/18/09, MarcioRibeiro wrote:
> From: MarcioRibeiro
> Subject: [R] Sum according observation
> To: r-help@r-project.org
> Received: Friday, September 18, 2009, 11:18 AM
>
> Hi listers,
> I have a simple doubt...
> I need to
I wish to identify groups representing different treatments, but to plot
them and do a regression using a continuous variable ("cover")
ignoring the groupings.
d$year <- NA
d$year <-c(rep(2007,12), rep(2008,12))
d$treatment <- c(rep("A",4),rep("B",4),rep("C",4), rep("A",4), rep("B",4),
rep("C",
See brief comment inline below.
A Singh wrote:
Bill,
It worked!!!
lmer(data=vcdf, peg.no~1 + (1|family/P1L55))
Linear mixed model fit by REML
Formula: peg.no ~ 1 + (1 | family/P1L55)
Data: vcdf
AIC BIC logLik deviance REMLdev
2981 2997 -1487 29762973
Random effects:
Groups
On Sep 18, 2009, at 5:24 PM, Edward Chen wrote:
Could someone explain to me briefly and point me to where I can find
help on
what the symbols $ and % mean in R? I have seen them in many others'
codes,
but I am still very unsure as to what they mean and what they do.
Thank you very much!
F
Dear R-helpers,
Can anyone suggest a useful alternative to Rgraphviz? I am trying to
create fairly simple graphs showing the structures of a hierarchical
cluster analysis or of a structural equation model. That is, I need
to be able to control the shape (rectangles vs ovals) of a limited
nu
Edward Chen-3 wrote:
>
> Could someone explain to me briefly and point me to where I can find help
> on
> what the symbols $ and % mean in R? I have seen them in many others'
> codes,
> but I am still very unsure as to what they mean and what they do.
> Thank you very much!
>
>
Help pages fo
Could someone explain to me briefly and point me to where I can find help on
what the symbols $ and % mean in R? I have seen them in many others' codes,
but I am still very unsure as to what they mean and what they do.
Thank you very much!
--
Edward Chen
Email: edche...@gmail.com
Cell Phone: 510-
Hi, all
In mgcv package, I tried to plot data.gam. However, residuals=TRUE doesn't
work for my data. No data points appear on the plot. What is the reason? The
number of the observation of my data set is almost 2000.
plot(data.gam,residuals=TRUE,shade=TRUE)
Thank you,
Lee
[[alternative
Hi,
On Sep 18, 2009, at 4:23 PM, Richard M. Heiberger wrote:
See the documentation for ESS in the ESS distribution
ess/doc/html/readme.html
There is even more detail in
ess/doc/html/ess.html
For the specific question about the emacs initialization file
~/.emacs,
that file is in your home
See the documentation for ESS in the ESS distribution
ess/doc/html/readme.html
There is even more detail in
ess/doc/html/ess.html
For the specific question about the emacs initialization file ~/.emacs,
that file is in your home directory which emacs will find.
The "~" abbreviation is required a
Bert,
Boy, to me that's one of those 'you have to know what it means to
know what it means' sort of things. Thanks for pointing it out though.
I appreciate it.
Cheers,
Mark
On Fri, Sep 18, 2009 at 1:09 PM, Bert Gunter wrote:
> It **IS** stated explicitly, though perhaps not so obviously, al
I am unable to install package lme4, after several attempts to do so using
various repository URLs.
Just to make sure everything works fine with proxy, connection, etc, I
installed ggplot2 and it worked fine.
I am using command
install.packages("lme4", lib="/myRlibs"),
optionally using contrib
It **IS** stated explicitly, though perhaps not so obviously, already in
the help file, In the "Note" section at the end it says:
"... This means that the recorded call is always of the form FUN(X[[0L]],
...), with 0L replaced by the current integer index. ..."
So you need to read more careful
That website says:
"Our components and applications for seamless integration allow to
embed statistics software from the R project and data analysis and
computation services from Scilab into applications on Microsoft
Windows, MacOS X and Linux."
Does anyone know if the claim to be supporti
Hi,
I decided to try emacs and ess with R, but to no avail. How are these
things suppose to work with R - or work, period? I downloaded the
latest windows versions of each and installed them as the documentation
says. But then the documentation for ess says to add (require
'ess-site) to /.
Hi Chris --
Christopher Bare wrote:
> Hi,
>
> I get an error indicating a missing library from the package 'Ruuid'.
> I suppose this means I should install RGtk. I just thought I'd
> document the error. Maybe a dependency entry is missing?
>
> R 2.9.0
> OS X 10.5.8
>
> Thanks,
>
> - chris
>
>
Thanks Duncan and Greg for the replies so far.
Duncan, many thanks for your continued work on this; please let us (or
at least me) know when your package will be available.
Greg, the DCOM option sounds great, but we run R on a Linux cluster,
and therefore it would be good to be able to write the
Bill,
It worked!!!
lmer(data=vcdf, peg.no~1 + (1|family/P1L55))
Linear mixed model fit by REML
Formula: peg.no ~ 1 + (1 | family/P1L55)
Data: vcdf
AIC BIC logLik deviance REMLdev
2981 2997 -1487 29762973
Random effects:
Groups NameVariance Std.Dev.
P1L55:family (
We are in the same boat (which I think is caused in my case by never
having been successful in installing a 64 bit version of Gtk+ on my
Mac, if such a beast exists). My errors are a tad bit different than
yours. Are you attempting this from an R64 version? I get no error
when I install Ruu
Hi,
I get an error indicating a missing library from the package 'Ruuid'.
I suppose this means I should install RGtk. I just thought I'd
document the error. Maybe a dependency entry is missing?
R 2.9.0
OS X 10.5.8
Thanks,
- chris
> biocLite('Ruuid')
Using R version 2.9.0, biocinstall version
Thanks Jim. That did the trick.
I had wondered in passing about that as all the examples in the
?lapply page were pretty simple and each time it was the first
argument. However I didn't read that this was a requirement so I
didn't go there. Is this really stated and I just cannot see it or
possibl
Dear All,
I have two factors: GROUP and PATIENT, where PATIENT is nested within
GROUP.
>levels(example$GROUP)
[1] "0" "1" "2" "3" "4"
> levels(example$PATIENT)
[1] "1" "2" "3"
There are three observations at each combination of these factors.
However, there are no observations for PATIEN
I thought some R-help readers might enjoy seeing the paper by Hal Varian on
predicting the present
using R and Google Trends that is linked via the following blog comment:
http://googleresearch.blogspot.com/2009/04/predicting-present-with-google-trends.html
Apologies in advance if this has alrea
-- Forwarded Message --
Date: 18 September 2009 19:24 +0100
From: A Singh
To: William Dunlap
Subject: RE: [R] Error: length(f1) == length(f2) is not TRUE
Yup, they are all factors- and its still doesn't work.
Getting to the stage where I can use 'summary()' is the problem- the
Change the order of the parameters in your function so that Lookback
is the first one. The first parameter of the lapply is what is passed
to the function as its first parameter. Now just have
ResultList <- lapply(x, DoAvgCalcs, IndexData=IndexData,
SampleSize=TestSamples, Iteration=TestIteratio
Hi,
On Sep 18, 2009, at 9:32 AM, vinay basavanal wrote:
Hi i can get sites that can r code on browser
Oh don't mean to sound rude, but can you try to rephrase your question?
I think a lot of people are having a hard time understanding what
you're really asking, but we'd be happy to help.
Hello,
Thanks for the correction, sorry Murat I was mistaken. Actually your
answers solved me a problem I was having using multiple fisher.test() on
nucleic acid sequences, where we come up with hundreds of thousands of p
values, a lot of which are 0's. Since we have to correct for multiple
te
Hello Thomas and Bryan,
Thanks for the correction, sorry Murat I was mistaken. Actually your
answers solved me a problem I was having using multiple fisher.test() on
nucleic acid sequences, where we come up with hundreds of thousands of p
values, a lot of which are 0's. Since we have to correct
This has something to do with your data.frame structure
see
> str(df1)
'data.frame': 3 obs. of 2 variables:
$ a : int 1 2 3
$ X1: 'AsIs' int [1:3, 1:2] 1 2 3 4 5 6
> str(df2)
'data.frame': 2 obs. of 2 variables:
$ a : int 1 2
$ X2: 'AsIs' int [1:2, 1:2] 11 12 13 14
This seems to work
Phil,
Thanks for the reply. Your suggestion is actually the one I started
with (assuming I'm understanding you) but I didn't seem to even get
down into my function, or the error message is from other place within
my function that I haven't discovered yet:
> x = seq(5:20)
> ResultList = lapply(x
On Fri, Sep 18, 2009 at 04:32:27AM -0700, premmad wrote:
>
> Sorry for confusing you all with my inexperienced posting .
> I tried as u said if you have 9 rows in the data it is working fine but
> please try out the same example as you have suggested earlier with morethan
> 9 rows.
>
> I tried it
The combn solution offered by Bill is great. It struck me that what you are
doing, in fact, is generating the null distribution of the two-sample Wilcoxon
test where the first group has size m and the second group has size n. In
general, the length of the array has size choose(n+m-1,m) which g
Try this:
with(DF, tapply(var2, var1, sum))
On Fri, Sep 18, 2009 at 12:18 PM, MarcioRibeiro wrote:
>
> Hi listers,
> I have a simple doubt...
> I need to manipulate the data base as:
>
> var1 var2
> 7 0.1
> 7 0.1
> 8 0.12
> 10 0.15
> 12 0.18
> 20 0.31
>
> I would like to
I read the original post as asking if there is something like odfWeave that
works for msword (I assumed windows, but I guess they could be asking about
MSword on other platforms, it just sounds like a windows shop).
But yes, sword only works on windows (and is in beta version still) and uses a
Hi i can get sites that can r code on browser
--
View this message in context:
http://www.nabble.com/R-on-browser-tp25508719p25508719.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://stat.ethz.
Mark -
The "l" in lapply refers to that fact that it will *return*
a list, not that it wants a list for input. You could input
a list, but then each element of the list would be one of the
values you wanted processed. So I think you want
x = seq(5:20)
ResultList = lapply(x, DoAvgCalcs, In
Hi listers,
I have a simple doubt...
I need to manipulate the data base as:
var1 var2
7 0.1
7 0.1
8 0.12
100.15
120.18
200.31
I would like to aggregate the equal cases as var1 making the sum of var2...
I would get...
var1 var2
7 0.2
8 0.12
100.15
120
Took me a minute to grok the gsubfn solution, but that is sweet! very nice.
thank you very much both for the suggestions,
Landon
--
View this message in context:
http://www.nabble.com/Simple-as.Date-question-dealing-with-a-timezone-offset-tp25491955p25512218.html
Sent from the R help mailing
Hi,
I'm trying to get better at things like lapply but it still stumps
me. I have a function I've written, tested and debugged using
individual calls to the function, ala:
ResultList5 = DoAvgCalcs(IndexData, Lookback=5,
SampleSize=TestSamples , Iterations=TestIterations )
ResultList8 = DoAvgC
I believe that their approach is based on DCOM and the post was about Office
Open XML.
We have had the ability to do this via DCOM for at least 6 years, but
unfortunately
DCOM is limited to Windows.
Greg Snow wrote:
> The people who brought us rexcel are working on sword which is a sweave for
The people who brought us rexcel are working on sword which is a sweave for ms
word, the current version is at:
http://rcom.univie.ac.at/download.html
hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -O
Jon Olav Skoien wrote:
> Hi,
>
> I want to cross-reference from the documentation of pkg1 to pkg2, which
> is imported in the NAMESPACE of pkg1, and under Depends in DESCRIPTION
> of pkg1. According to "Writing R extensions", this can be done by:
> \code{\link{foo}}
> when foo is an aliased functi
Hi Duncan
>> You can try putting this in your Rprofile
>> options("keep.source=F")
>>
>> This will work in the R cmd but it will not work in the RGui
>>
>
> The syntax is wrong there: that should be options(keep.source=F). But I
> don't think it addresses either question.
I was working from my
Hi Bill,
Thanks, I did try out what you suggested but it doesn't seem to work.
I get the same error again.
There's obviously something here that I don't get. Need to figure it out.
Aditi
--On 18 September 2009 08:34 -0700 William Dunlap wrote:
From: r-help-boun...@r-project.org
[mailto:r-he
Tobias Sing wrote:
> Dear Duncan and other R users,
>
> The department in which I work will soon make some decisions to
> improve our reporting. Since I hope that our solution will support R
> and Sweave-like functionality (otherwise it wouldn't be an
> improvement), I hope it's ok to repeat
Rolf,
I no longer claim to be young, the naïve part is still up for debate,
but I find that restricting the null to only include = to be more confusing
than to have it include the inequality. To have the alternative be > and the
null be = implies that we are working on the assumption
Dear Duncan and other R users,
The department in which I work will soon make some decisions to
improve our reporting. Since I hope that our solution will support R
and Sweave-like functionality (otherwise it wouldn't be an
improvement), I hope it's ok to repeat my question back from June
if th
It appears that you have a fundamental misunderstanding of what p-values do and
do not say (though this misunderstanding is commom). The following article
addresses this issue and could help with a better understanding:
Murdock, D, Tsai, Y, and Adcock, J (2008) _P-Values are Random
Va
use "View" to view the dataframe.
On Fri, Sep 18, 2009 at 8:17 AM, premmad wrote:
>
> Thanks .I tried its working but when i tried to view the dataframe i got the
> following error
> Error in edit.data.frame(get(subx, envir = parent), title = subx, ...) :
> can only handle vector and factor elem
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of A Singh
> Sent: Friday, September 18, 2009 4:42 AM
> To: r-help@r-project.org
> Subject: [R] Error: length(f1) == length(f2) is not TRUE
>
>
> Dear R users,
>
> I am trying to fit an lmer model with only r
You are going to have to order your values for comparison. Use
'strsplit' to split on the comma, then rejoin the data items based on
the sorting order.
On Fri, Sep 18, 2009 at 8:47 AM, Juliane Struve
wrote:
> Dear list,
>
> I am using match() to match pairs of locations, e.g. trip="loc1,loc2" fr
I just wanted to know whether the chances of getting help with this would
be greater if I posted this on the mixed models list, even though I would
be cross-posting.. ?
--On 18 September 2009 12:41 +0100 A Singh wrote:
Dear R users,
I am trying to fit an lmer model with only random effects
> I am using gam in gam package (not in mgcv) it is possible to force
> gam in mgcv to behave like gam in gam package?
-- not *exactly*, no. But what do you want to do? (i.e. what feature of `gam'
do you need?)
--
> Simon Wood, Mathematical Sciences, University of Bath, Bath, BA2 7AY UK
> +
Try this:
> as.POSIXct(format(as.Date("2008-07-01")))
[1] "2008-07-01 EDT"
See R News 4/1 for more.
On Fri, Sep 18, 2009 at 10:19 AM, Markus Loecher
wrote:
> Dear R users,
> I am struggling a bit with the converting dates to full POSIX timestamps, in
> particular, I would like to somehow force
On Sep 18, 2009, at 7:58 AM, premmad wrote:
Thanks for the reply and it is useful.What i want to know here is
i'm going
to try and write an automated procedure using batch processing in R
by the
way input of the next step is going to be this steps output .so one
will not
able to predict
Gábor Csárdi wrote:
> On Thu, Sep 17, 2009 at 5:59 PM, Martin Morgan wrote:
>> Gábor Csárdi wrote:
>>> Dear All,
>>>
>>> maybe this is something obvious, I seem to be incapable of
>>> understanding how S4 works.
>>>
>>> So, in package 'A' I defined a "summary" method for my class:
>>>
>>> setMetho
On 9/18/2009 9:05 AM, Steve Lianoglou wrote:
Hi,
On Sep 18, 2009, at 8:31 AM, Katrine Damgaard wrote:
Hey everybody!
We have created our own package, and need to do some corrections in
the R-code of one of the function included in the package.
How can I do that. I have read a manual how to c
I'm trying to obtain within-group correlations on a subset of variables. I
first selected my variables using the following command:
mydata$x<-mydata[c("iq","education","achievement")]
I'd like to look at correlations among those variables separately for men
and women. My gender variable in mydata
Dear R users,
I am struggling a bit with the converting dates to full POSIX timestamps, in
particular, I would like to somehow force the timezone to be local, i.e. the
output of
as.POSIXct(as.Date("2008-07-01")) should always be equal to "2008-07-01
00:00:00", is that achievable ? I tried to set th
Try this:
x[mapply(function(x, y)all(x %in% y), strsplit(x, ','), strsplit(trip, ','))]
On Fri, Sep 18, 2009 at 9:47 AM, Juliane Struve
wrote:
> Dear list,
>
> I am using match() to match pairs of locations, e.g. trip="loc1,loc2" from a
> list of such pairs, e.g. list=("loc1,loc2", "loc1,loc3",
Hi,
I want to cross-reference from the documentation of pkg1 to pkg2, which
is imported in the NAMESPACE of pkg1, and under Depends in DESCRIPTION
of pkg1. According to "Writing R extensions", this can be done by:
\code{\link{foo}}
when foo is an aliased function in the documentation of pkg2.
On Thu, Sep 17, 2009 at 5:59 PM, Martin Morgan wrote:
> Gábor Csárdi wrote:
>> Dear All,
>>
>> maybe this is something obvious, I seem to be incapable of
>> understanding how S4 works.
>>
>> So, in package 'A' I defined a "summary" method for my class:
>>
>> setMethod("summary", signature(object="
Here is an example:
> x <- c('loc1,loc2', 'loc2,loc3', 'loc2,loc1', 'loc3,loc1')
> x.s <- strsplit(x, ',')
> # now sort them
> x.s <- sapply(x.s, sort)
> # create new output
> unique(apply(x.s, 2, paste, collapse=','))
[1] "loc1,loc2" "loc2,loc3" "loc1,loc3"
>
On Fri, Sep 18, 2009 at 8:47 AM, Ju
Hi,
I have a simple question on interpreting output results from your msm
package in R when using a categorical model with hcovariates i.e.
covariates on the parameters of the emission model. The interpretation
is straightforward for normal distributions, etc. but when using
categorical distrib
No box is easy,
bwplot(y~x, data=data.frame(y=rnorm(10),x=sample(letters[1:3],10,repl=T)),
par.settings=list(axis.line=list(col=NA)))
but that seems to remove all axis lines and ticks as well. You may
have to define a custom panel.axis() function.
An alternative is to use grid.remove() to remove
Hi,
On Sep 18, 2009, at 8:31 AM, Katrine Damgaard wrote:
Hey everybody!
We have created our own package, and need to do some corrections in
the R-code of one of the function included in the package.
How can I do that. I have read a manual how to create an R package,
but I can't find anythin
The test that a slope differs by group is a test that the
variable*group interaction equals
zero (overall test). Maybe searching post-hoc comparisons in
regression will give you some
leads.
On Tue, Sep 15, 2009 at 10:57 AM, Jun Shen wrote:
> Hi, all,
>
> I am thinking to compare a group of slopes
Hey everybody!
We have created our own package, and need to do some corrections in the R-code
of one of the function included in the package.
How can I do that. I have read a manual how to create an R package, but I can't
find anything about updating R-code in the package.
Best regards,
Katrine
Thank you again for your reply! What I would like to do is to class
my sample into two group (0,1). I am not sure which method to apply
and whether the svm is the correct one! However, when I apply the
below R code I get two group the samples in TRUE and FALSE. Can I
take this result to put
Thanks for the reply and it is useful.What i want to know here is i'm going
to try and write an automated procedure using batch processing in R by the
way input of the next step is going to be this steps output .so one will not
able to predict the lines please also do answer in taking consideratio
Dear list,
I am using match() to match pairs of locations, e.g. trip="loc1,loc2" from a
list of such pairs, e.g. list=("loc1,loc2", "loc1,loc3",
"loc2,loc3","loc2,loc1").
In this example match() will match "trip" with the first element of "list", but
not the 4th, because the order is revers
Sorry for confusing you all with my inexperienced posting .
I tried as u said if you have 9 rows in the data it is working fine but
please try out the same example as you have suggested earlier with morethan
9 rows.
I tried it as following
datetime <-c(
+ "01OCT1987:00:00:00.000",
+ "12APR2004:0
Thanks .I tried its working but when i tried to view the dataframe i got the
following error
Error in edit.data.frame(get(subx, envir = parent), title = subx, ...) :
can only handle vector and factor elements
--
View this message in context:
http://www.nabble.com/Datetime-conversion-tp25503
I am new to R and I want to solve this following problem using R.
My Objective function is a linear function with Quadratic constraints.I want
to know how to solve this problem and which package will be helpful for me
for solving such type of problems.Moreover my one constraint is linear and
equa
Dear matt,
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
> Behalf Of Bunny, lautloscrew.com
> Sent: September-18-09 6:18 AM
> To: r-help@r-project.org
> Subject: [R] some irritation with heteroskedasticity testing
>
> Dear all,
>
> Try
Your problem is that 'strptime' returns an object of POSIXlt type
which is 9 elements; what you what is: ( you need a POSIXct type)
dt$new<-as.POSIXct(strptime(as.character(dt$datetime),"%d%b%Y"))
On Fri, Sep 18, 2009 at 6:26 AM, premmad wrote:
>
> It works but what i need is the result also as
> 1.) How do I make lattice (e.g. barchart) to not draw a box but only a
> y-axis on the left hand side so that the plot looks like barplot with
> default settings?
Does nobody have an idea? Or is the solution that obvious?
__
R-help@r-project.org maili
On 9/18/2009 5:49 AM, premmad wrote:
I tried running 50 lines of ifelse statement in R and the system says context
stack overflow at 50 line.Is it the limitation of R or is there any way
around that can be done to overcome this.Thanks
You can always break it up into multiple lines. For example
Dear R users,
I am trying to fit an lmer model with only random effects which is giving
me the following error:
Error : length(f1) == length(f2) is not TRUE
In addition: Warning messages:
1: In P1L55:family :
numerical expression has 390 elements: only the first used
2: In P1L55:family :
nu
On Fri, Sep 18, 2009 at 12:59:16PM +0200, Philipp Pagel wrote:
> > foo$B <- as.numeric(sub(',', '', as.character(foo$B)))
Thinking about it some more, you should use gsub instead of sub here.
Otherwise only the first occurrence of the thousands separator will be
removed.
cu
Philipp
--
Can you post a reproducible code snippet, along with the output/error
messages, and the output of sessionInfo(). That way other folks on R-help
may be able to offer help.
Here's myl output of sessionInfo()
> sessionI
> The same what you have worked out is my need but i'm getting the following
> error
> Error in `$<-.data.frame`(`*tmp*`, "date", value = list(sec = c(0, 0, :
> replacement has 9 rows, data has 14
Please give more detail about what you did. This error is certainly
not from the example used i
On Fri, Sep 18, 2009 at 03:46:27PM +1000, Steven Kang wrote:
> *Q1. Are there any way of suppressing the commands in the R console?*
I think this has been answered already.
> *Q2. Is R capable of reading numbers that are represented with 1,000
> separator commas?*
I am not aware of an option to
The same what you have worked out is my need but i'm getting the following
error
Error in `$<-.data.frame`(`*tmp*`, "date", value = list(sec = c(0, 0, :
replacement has 9 rows, data has 14
Please help me in this
--
View this message in context:
http://www.nabble.com/Datetime-conversion-tp2
It works but what i need is the result also as a column .
I tried using the following code .
dt$new<-strptime(as.character(dt$datetime),"%d%b%Y.
It shows the following error
Error in `$<-.data.frame`(`*tmp*`, "Sa_dt", value = list(sec = c(0, 0, :
replacement has 9 rows, data has 14.
Please h
I tried running 50 lines of ifelse statement in R and the system says context
stack overflow at 50 line.Is it the limitation of R or is there any way
around that can be done to overcome this.Thanks
--
View this message in context:
http://www.nabble.com/Maximum-No.of-code-in-R-tp25506024p25506024
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