Your problem is that 'strptime' returns an object of POSIXlt type which is 9 elements; what you what is: ( you need a POSIXct type)
dt$new<-as.POSIXct(strptime(as.character(dt$datetime),"%d%b%Y")) On Fri, Sep 18, 2009 at 6:26 AM, premmad <mtechp...@gmail.com> wrote: > > It works but what i need is the result also as a column . > I tried using the following code . > dt$new<-strptime(as.character(dt$datetime),"%d%b%Y. > It shows the following error > > Error in `$<-.data.frame`(`*tmp*`, "Sa_dt", value = list(sec = c(0, 0, : > replacement has 9 rows, data has 14. > > Please help me to solve this > -- > View this message in context: > http://www.nabble.com/Datetime-conversion-tp25503138p25506438.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve? ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
