On Fri, Sep 18, 2009 at 04:32:27AM -0700, premmad wrote:
>
> Sorry for confusing you all with my inexperienced posting .
> I tried as u said if you have 9 rows in the data it is working fine but
> please try out the same example as you have suggested earlier with morethan
> 9 rows.
>
> I tried it as following
> datetime <-c(
> + "01OCT1987:00:00:00.000",
> + "12APR2004:00:00:00.000",
> + "01DEC1987:00:00:00.000",
> + "01OCT1975:00:00:00.000",
> + "01AUG1979:00:00:00.000",
> + "26JUN2003:00:00:00.000",
> + "01JAN1900:00:00:00.000",
> + "13MAY1998:00:00:00.000",
> + "30SEP1998:00:00:00.000",
> + "30SEP1998:00:00:00.000",
> + "30SEP1998:00:00:00.000",
> + "30SEP1998:00:00:00.000")
> dt <- as.data.frame(datetime)
>
> dt$date<-strptime(as.character(dt$datetime),"%d%b%Y")
>
> and got the following error :
>
> Error in `$<-.data.frame`(`*tmp*`, "date", value = list(sec = c(0, 0, :
> replacement has 9 rows, data has 12.
Oops - sorry you are right. There is a Problem with inserting the
object. Try this instead:
dt$date <- as.Date(dt$datetime, "%d%b%Y")
cu
Philipp
--
Dr. Philipp Pagel
Lehrstuhl für Genomorientierte Bioinformatik
Technische Universität München
Wissenschaftszentrum Weihenstephan
85350 Freising, Germany
http://webclu.bio.wzw.tum.de/~pagel/
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