Xah Lee wrote:
> I think it would be a improvement for the built-in range() so that step
> needs not be an integer. [...]
>
> Range( 5, 7, 0.3); # returns [5, 5.3, 5.6, 5.9, 6.2, 6.5, 6.8]
This may not return what you expect it to return.
For example let's use a naive implementation like this:
Xah Lee wrote:
> on a related topic,
> I think it would be a improvement for the built-in range() so that step
> needs not be an integer.
There are easy workarounds but I'd find it useful as well.
> Further, it'd be better to support decreasing range. e.g.
>
> Range( 5, 7, 0.3); # returns [5, 5.
Thanks to all for the reply. (i should've known better)
on a related topic,
I think it would be a improvement for the built-in range() so that step
needs not be an integer.
Further, it'd be better to support decreasing range. e.g.
Range( 5, 7, 0.3); # returns [5, 5.3, 5.6, 5.9, 6.2, 6.5, 6.8]
Ran
> def Range(n,m=None,step=1):
> if m is None:
> n,m = 0,n+1
> else:
> n,m = n,m+1
> return range(n,m,step)
i like this one.
coming from php (just a couple weeks ago) its always again interesting
to see how i have to start thinking to program differently, it can be
so much easier wi
On Fri, 13 May 2005 02:52:34 -0700, Xah Lee wrote:
> i wanted to define a function where the number of argument matters.
> Example:
>
> def Range(n):
> return range(n+1)
>
> def Range(n,m):
> return range(n,m+1)
>
> def Range(n,m,step):
> return range(n,m+1,step)
>
> this obvious d
On Fri, 13 May 2005 11:52:34 +0200, Xah Lee <[EMAIL PROTECTED]> wrote:
> i wanted to define a function where the number of argument matters.
> Example:
>
> def Range(n):
> return range(n+1)
>
> def Range(n,m):
> return range(n,m+1)
>
> def Range(n,m,step):
> return range(n,m+1,step)
>
On 13 May 2005 02:52:34 -0700,
"Xah Lee" <[EMAIL PROTECTED]> wrote:
> i wanted to define a function where the number of argument matters.
> Example:
> def Range(n):
> return range(n+1)
> def Range(n,m):
> return range(n,m+1)
> def Range(n,m,step):
> return range(n,m+1,step)
> this
On 5/13/05, Wolfram Kriesing <[EMAIL PROTECTED]> wrote:
> using default args does actually solve it
> what about
> def Range(n, m=None, step=None)
> if step==None:
> if m==None:
> range(n)
> else:
<...snip...>
or better still :
def Range(*args):
return range(*args)
Regards
using default args does actually solve it
what about
def Range(n, m=None, step=None)
if step==None:
if m==None:
range(n)
else:
range(n,m)
else:
if m==None:
raise Exception, "missing parameter m"
else:
range(n,m,step)
can be optimized i am sure :-)
--
i wanted to define a function where the number of argument matters.
Example:
def Range(n):
return range(n+1)
def Range(n,m):
return range(n,m+1)
def Range(n,m,step):
return range(n,m+1,step)
this obvious doesn't work. The default argument like
Range(n=1,m,step=1) obviously isn't a s
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