On 13 May 2005 02:52:34 -0700,
"Xah Lee" <[EMAIL PROTECTED]> wrote:
> i wanted to define a function where the number of argument matters.
> Example:
> def Range(n):
> return range(n+1)
> def Range(n,m):
> return range(n,m+1)
> def Range(n,m,step):
> return range(n,m+1,step)
> this obvious doesn't work. The default argument like
> Range(n=1,m,step=1) obviously isn't a solution.
> can this be done in Python?
Assuming you're doing something more interesting than wrapping range:
def Range( start, stop = None, step = 1 ):
if stop == None: # i,e., we only got one argument
stop = start
start = 1
# rest of function goes here....
HTH,
Dan
--
Dan Sommers
<http://www.tombstonezero.net/dan/>
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http://mail.python.org/mailman/listinfo/python-list
