On Fri, 13 May 2005 02:52:34 -0700, Xah Lee wrote:
> i wanted to define a function where the number of argument matters.
> Example:
>
> def Range(n):
> return range(n+1)
>
> def Range(n,m):
> return range(n,m+1)
>
> def Range(n,m,step):
> return range(n,m+1,step)
>
> this obvious doesn't work. The default argument like
> Range(n=1,m,step=1) obviously isn't a solution.
>
> can this be done in Python?
>
> or, must the args be changed to a list?
>
def Range(n,m=None,step=1):
if m is None:
n,m = 0,n+1
else:
n,m = n,m+1
return range(n,m,step)
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