using default args does actually solve it
what about
def Range(n, m=None, step=None)
if step==None:
if m==None:
range(n)
else:
range(n,m)
else:
if m==None:
raise Exception, "missing parameter m"
else:
range(n,m,step)
can be optimized i am sure :-)
--
cu
Wolfram
On 13 May 2005 02:52:34 -0700, Xah Lee <[EMAIL PROTECTED]> wrote:
> i wanted to define a function where the number of argument matters.
> Example:
>
> def Range(n):
> return range(n+1)
>
> def Range(n,m):
> return range(n,m+1)
>
> def Range(n,m,step):
> return range(n,m+1,step)
>
> this obvious doesn't work. The default argument like
> Range(n=1,m,step=1) obviously isn't a solution.
>
> can this be done in Python?
>
> or, must the args be changed to a list?
>
> Xah
> [EMAIL PROTECTED]
> ∑ http://xahlee.org/
>
> --
> http://mail.python.org/mailman/listinfo/python-list
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