finally i searched dict.values()[index] solved this
On Saturday, July 1, 2017 at 6:00:41 PM UTC+8, Peter Otten wrote: > Ho Yeung Lee wrote: > > > expect result as this first case > > > > ii = 0 > > jj = 0 > > for ii in range(0,3): > > for jj in range(0,3): > > if ii < jj: > > print (ii, jj) > > > > > > but below is different > > as sometimes the situation is not range(0,3), but it a a list of tuple > > > > iiii = 0 > > > for ii in range(0,3): > # jj starts with 0 on invocation of the inner loop > # to get that with an independent counter you have to > #initialise it explicitly: > jjjj = 0 > > for jj in range(0,3): > > if iiii < jjjj: > > print (iiii, jjjj) > > jjjj = jjjj + 1 > > iiii = iiii + 1 > > > > how to make this situation return result like the first case? > > Because you don't reset jjjj the condition iiii < jjjj is always True the > second and third time the inner loop is executed. -- https://mail.python.org/mailman/listinfo/python-list
