Ho Yeung Lee wrote:
> expect result as this first case
>
> ii = 0
> jj = 0
> for ii in range(0,3):
> for jj in range(0,3):
> if ii < jj:
> print (ii, jj)
>
>
> but below is different
> as sometimes the situation is not range(0,3), but it a a list of tuple
>
> iiii = 0
> for ii in range(0,3):
# jj starts with 0 on invocation of the inner loop
# to get that with an independent counter you have to
#initialise it explicitly:
jjjj = 0
> for jj in range(0,3):
> if iiii < jjjj:
> print (iiii, jjjj)
> jjjj = jjjj + 1
> iiii = iiii + 1
>
> how to make this situation return result like the first case?
Because you don't reset jjjj the condition iiii < jjjj is always True the
second and third time the inner loop is executed.
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