i got an idea with below, but it can not compile
for ii, yy in range(2,5), range(0,3):
for jj, zz in range(2,5), range(0,3):
if yy < zz:
print (ii, jj)
real situation
groupkey
{(0, 1): [[0, 1], [0, 2], [0, 8]], (1, 2): [[1, 5], [1, 9], [2, 6], [2, 10],
[8, 9], [8, 10]], (2, 3): [[5, 7], [6, 7], [6, 14], [10, 14]]}
ii = 0
jj = 0
for groupkeya in groupkey:
for groupkeyb in groupkey:
if ii < jj:
print "groupkeya"
print groupkeya, ii, jj
print "groupkeyb"
print groupkeyb, ii, jj
jj = jj + 1
ii = ii + 1
On Saturday, July 1, 2017 at 5:05:48 PM UTC+8, Ho Yeung Lee wrote:
> sorry for typo,
>
> iiii = 0
> jjjj = 0
> for ii in range(0,3):
> for jj in range(0,3):
> if iiii < jjjj:
> print (ii, jj) <----- correct here
> jjjj = jjjj + 1
> iiii = iiii + 1
>
>
> On Saturday, July 1, 2017 at 4:55:59 PM UTC+8, Ho Yeung Lee wrote:
> > expect result as this first case
> >
> > ii = 0
> > jj = 0
> > for ii in range(0,3):
> > for jj in range(0,3):
> > if ii < jj:
> > print (ii, jj)
> >
> >
> > but below is different
> > as sometimes the situation is not range(0,3), but it a a list of tuple
> >
> > iiii = 0
> > jjjj = 0
> > for ii in range(0,3):
> > for jj in range(0,3):
> > if iiii < jjjj:
> > print (iiii, jjjj)
> > jjjj = jjjj + 1
> > iiii = iiii + 1
> >
> > how to make this situation return result like the first case?
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