sorry for typo, iiii = 0 jjjj = 0 for ii in range(0,3): for jj in range(0,3): if iiii < jjjj: print (ii, jj) <----- correct here jjjj = jjjj + 1 iiii = iiii + 1
On Saturday, July 1, 2017 at 4:55:59 PM UTC+8, Ho Yeung Lee wrote: > expect result as this first case > > ii = 0 > jj = 0 > for ii in range(0,3): > for jj in range(0,3): > if ii < jj: > print (ii, jj) > > > but below is different > as sometimes the situation is not range(0,3), but it a a list of tuple > > iiii = 0 > jjjj = 0 > for ii in range(0,3): > for jj in range(0,3): > if iiii < jjjj: > print (iiii, jjjj) > jjjj = jjjj + 1 > iiii = iiii + 1 > > how to make this situation return result like the first case? -- https://mail.python.org/mailman/listinfo/python-list