I prefer itertools.chain.from_iterable to the sum trick.
>>> from itertools import chain
>>> lst = list('abc')
>>> list(chain.from_iterable([s]*3 for s in lst))
['a', 'a', 'a', 'b', 'b', 'b', 'c', 'c', 'c']
On Tue, Mar 29, 2016 at 5:28 PM Vito De Tullio <vito.detul...@gmail.com>
wrote:
> Random832 wrote:
>
> > How do you turn ['a', 'c', 'b'] into ['a', 'a', 'a', 'c', 'c', 'c', 'b',
> > 'b', 'b']?
>
> >>> sum([[e]*3 for e in ['a', 'c', 'b']], [])
> ['a', 'a', 'a', 'c', 'c', 'c', 'b', 'b', 'b']
>
>
> --
> By ZeD
>
> --
> https://mail.python.org/mailman/listinfo/python-list
>
--
https://mail.python.org/mailman/listinfo/python-list
