On Saturday, March 26, 2016 at 11:12:58 PM UTC+1, beli...@aol.com wrote:
> I can create a list that has repeated elements of another list as follows:
>
> xx = ["a","b"]
> nrep = 3
> print xx
> yy = []
> for aa in xx:
> for i in range(nrep):
> yy.append(aa)
> print yy
>
> output:
> ['a', 'b']
> ['a', 'a', 'a', 'b', 'b', 'b']
>
> Is there a one-liner to create a list with repeated elements?
What about this?
def rep_elements(sequence, nrep):
#return [ritem for item in sequence for ritem in [item]*nrep]
return list(chain.from_iterable(([item]*nrep for item in sequence)))
sequence = ['h','o','l','a']
print(rep_elements(sequence, 3))
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