On Saturday, March 26, 2016 at 7:30:14 PM UTC-4, Mark Lawrence wrote: > On 26/03/2016 22:12, beliavsky--- via Python-list wrote: > > I can create a list that has repeated elements of another list as follows: > > > > xx = ["a","b"] > > nrep = 3 > > print xx > > yy = [] > > for aa in xx: > > for i in range(nrep): > > yy.append(aa) > > print yy > > > > output: > > ['a', 'b'] > > ['a', 'a', 'a', 'b', 'b', 'b'] > > > > Is there a one-liner to create a list with repeated elements? > > > > yy = [aa for aa in xx for _ in range(nrep)] > > I suggest that you try this sort of the thing at an interactive prompt, > it's a great way to learn. > > You might also want to take a look at the itertools module > https://docs.python.org/3/library/itertools.html. This is often used in > building structures like the ones you've been asking about today. To me > it is the Swiss Army Knife of the stdlib.
Thanks for the one-liner, which I prefer to the one I made up using itertools: yy = list(chain.from_iterable([list(repeat(aa,nrep)) for aa in xx])) -- https://mail.python.org/mailman/listinfo/python-list
