On Sunday, March 27, 2016 at 10:02:44 AM UTC+2, Antonio Caminero Garcia wrote: > On Saturday, March 26, 2016 at 11:12:58 PM UTC+1, beli...@aol.com wrote: > > I can create a list that has repeated elements of another list as follows: > > > > xx = ["a","b"] > > nrep = 3 > > print xx > > yy = [] > > for aa in xx: > > for i in range(nrep): > > yy.append(aa) > > print yy > > > > output: > > ['a', 'b'] > > ['a', 'a', 'a', 'b', 'b', 'b'] > > > > Is there a one-liner to create a list with repeated elements? > > What about this? > > def rep_elements(sequence, nrep): > #return [ritem for item in sequence for ritem in [item]*nrep] > return list(chain.from_iterable(([item]*nrep for item in sequence))) > > sequence = ['h','o','l','a'] > print(rep_elements(sequence, 3))
I prefer the commented solution :). [ritem for item in sequence for ritem in [item]*nrep] # O(len(sequence)*2nrep) and the chain solution would be # O(len(sequence)*nrep). The constants ate gone so I prefer the first one for its readibility. On a practical level: https://bpaste.net/show/fe3431a13732 -- https://mail.python.org/mailman/listinfo/python-list
