Am 14.10.2018 um 09:41 schrieb John Darrington:
Which is why I suggested using one of the CDF functions. There is no T function, but there is a F function, which I think is the same if you set DF2 to 1. But you probably know better than me about those details. Perhaps IDF.F (0.05, N -1, 1) is what Werner wants (I haven't tried it)?
Ok. I see. I think the t distribution is implemented in PSPP. IDF.T(0.975, n-1) gives the correct t value for a 95% CI. Werner could try it.
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