On Mon, 2003-11-24 at 10:38, Bernhard Praschinger wrote:

> But that does not tell you the average bitrate. But you can easly
> calculate the average bitrate:
> filesize / (number of frame / framerate) = bytes/sec *8 = bits/sec


hello,
i am trying to learn how to calculate the bitrate.  i 
encoded a CBR mpeg so i could figure out how to calculate it.  i
am still off a little bit and dont know why ?

the source avi is a DV camcorder capture,NTSC,29.97fps

i encoded with this command;
$ lav2yuv video.eli | mpeg2enc -o video.m2v

from the faq it says if i use these switches i am creating a video
file with a default bitrate of 1152kBit/sec.  ( VCD)

mpeg2enc says i have  3475 frames:

INFO: [mpeg2enc] Signalling last frame = 3475
INFO: [mpeg2enc] Frame end 3471 P quant=12.33 total act=177010.51095
INFO: [mpeg2enc] Frame end 3472 B quant=13.69 total act=177042.15341
INFO: [mpeg2enc] Frame end 3473 B quant=13.99 total act=177073.44669
INFO: [mpeg2enc] Frame end 3474 P quant=12.70 total act=177106.62586
INFO: [mpeg2enc] Frame end 3475 B quant=12.65 total act=177136.90095
INFO: [mpeg2enc] Guesstimated final muxed size = 16700455

now i use the formula to figure out what my file size should have been.

3475 frames / 29.97 fps = 115.94 seconds of video
and
1152kBit / 8 = 144KByte video bitrate

so

X (filesize in KBytes) / 115.94 seconds = 144Kbytes video rate

X = 16695.36 Kbytes   or (16695.36 * 1024) 17096048 bytes

but what is have is less than that

[EMAIL PROTECTED] capture]$ ls -l video.m2v
-rw-rw-r--    1 rperkins rperkins 16272944 Nov 27 01:53 video.m2v

if i plug the actual file size and solve for video rate
my rate comes out to 1096.5 Kbps when it was suppossed to be 1152 Kbps

i would think this should come out exact ?
so where did i go wrong ?

thanks

randy



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