Rely on regex to find the version number, rather than rely on numerical input
to be found in a particular input field.
Proposed implementation also eliminates the necessity to invoke 'grep' + 'awk'.
Tested on:
Oracle Linux
Signed-off-by: Alexander Kapshuk <alexander.kaps...@gmail.com>
---
scripts/ver_linux | 8 ++++++--
1 file changed, 6 insertions(+), 2 deletions(-)
diff --git a/scripts/ver_linux b/scripts/ver_linux
index d5b342e..af5ac82 100755
--- a/scripts/ver_linux
+++ b/scripts/ver_linux
@@ -94,8 +94,12 @@ awk '/version/{
substr($0,RSTART,RLENGTH))
}'
-pppd --version 2>&1| grep version | awk \
-'NR==1{print "PPP ", $3}'
+pppd --version 2>&1 |
+awk '/version/{
+ match($0, /[0-9]+([.]?[0-9]+)+/)
+ printf("PPP\t\t\t%s\n",
+ substr($0,RSTART,RLENGTH))
+}'
isdnctrl 2>&1 | grep version | awk \
'NR==1{print "isdn4k-utils ", $NF}'
--
2.4.9
--
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