Rely on regex to find the version number, rather than rely on numerical input
to be found in a particular input field.
Tested on:
Gentoo Linux
Signed-off-by: Alexander Kapshuk <alexander.kaps...@gmail.com>
---
scripts/ver_linux | 8 ++++++--
1 file changed, 6 insertions(+), 2 deletions(-)
diff --git a/scripts/ver_linux b/scripts/ver_linux
index f839be3..ae426c2 100755
--- a/scripts/ver_linux
+++ b/scripts/ver_linux
@@ -171,8 +171,12 @@ awk '/[0-9]+([.]?[0-9]+)+/ && !/not found$/{
substr($0,RSTART,RLENGTH))
}'
-iwconfig --version 2>&1 | awk \
-'(NR==1 && ($3 == "version")) {print "wireless-tools ",$4}'
+iwconfig --version 2>&1 |
+awk '/version/{
+ match($0, /[0-9]+([.]?[0-9]+)+/)
+ printf("Wireless-tools\t\t%s\n",
+ substr($0,RSTART,RLENGTH))
+}'
if [ -e /proc/modules ]; then
X=`cat /proc/modules | sed -e "s/ .*$//"`
--
2.4.9
--
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