Rely on regex to find the version number, rather than rely on numerical input
to be found in a particular input field.
Proposed implementation also eliminates the necessity to invoke 'grep' + 'awk'.
Signed-off-by: Alexander Kapshuk <alexander.kaps...@gmail.com>
---
scripts/ver_linux | 8 ++++++--
1 file changed, 6 insertions(+), 2 deletions(-)
diff --git a/scripts/ver_linux b/scripts/ver_linux
index 7d85447..65d4c02 100755
--- a/scripts/ver_linux
+++ b/scripts/ver_linux
@@ -60,8 +60,12 @@ awk '/version/{
substr($0,RSTART,RLENGTH))
}'
-reiserfsck -V 2>&1 | grep ^reiserfsck | awk \
-'NR==1{print "reiserfsprogs ", $2}'
+reiserfsck -V 2>&1 |
+awk '/^reiserfsck/{
+ match($0, /[0-9]+([.]?[0-9]+)+/)
+ printf("Reiserfsprogs\t\t%s\n",
+ substr($0,RSTART,RLENGTH))
+}'
fsck.reiser4 -V 2>&1 | grep ^fsck.reiser4 | awk \
'NR==1{print "reiser4progs ", $2}'
--
2.4.9
--
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