Rely on regex to find the version number, rather than rely on numerical input
to be found in a particular input field.
Proposed implementation also eliminates the necessity to invoke 'grep' + 'sed'
+ 'awk'.
Signed-off-by: Alexander Kapshuk <alexander.kaps...@gmail.com>
---
scripts/ver_linux | 8 ++++++--
1 file changed, 6 insertions(+), 2 deletions(-)
diff --git a/scripts/ver_linux b/scripts/ver_linux
index 2e1929f..7d85447 100755
--- a/scripts/ver_linux
+++ b/scripts/ver_linux
@@ -53,8 +53,12 @@ awk '/^tune2fs/{
substr($0,RSTART,RLENGTH))
}'
-fsck.jfs -V 2>&1 | grep version | sed 's/,//' | awk \
-'NR==1 {print "jfsutils ", $3}'
+fsck.jfs -V 2>&1 |
+awk '/version/{
+ match($0, /[0-9]+([.]?[0-9]+)+/)
+ printf("Jfsutils\t\t%s\n",
+ substr($0,RSTART,RLENGTH))
+}'
reiserfsck -V 2>&1 | grep ^reiserfsck | awk \
'NR==1{print "reiserfsprogs ", $2}'
--
2.4.9
--
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