Bill Manning <[EMAIL PROTECTED]> writes:

> % So, how many /20s are there in IPv6?
> 
> The same as IPv4.  Oh, you mean the number of prefixs that
> carry the same number of end-node addresses as an IPv4 /20?
> That would equate to the number of /116's in IPv6 parlance.

So how many /20s or how many /116s will fit into a routing table?

Alternatively -- if we take Harald Alvestrand's numbers,
and assume everyone who wants one gets an IPv6 /48,
leaving 16 bits for subnetting before the "flat space" --
can we try to quantify the consumption of critical
resources in routers with this as an explicit goal?

(I think it's fair to make assumptions that we will
continue with BGP and the iBGP hack, and known mitigations
of the n**2 iBGP problem.  I think it'd also be
fair to consider time/space tradeoffs in the BGP
data structures and the data structures associated with
the actual forwarding of packets.)

        Sean.

Reply via email to