在2020年11月14日星期六 UTC+8 上午3:09:24<Gregg Townsend> 写道：
> If I understand what you're trying to do, I'd approach it this way, using
> a generously buffered channel and discarding the extras at the consumer, as
> shown below, instead of at the producer:
>
> result <- c // wait for result to appear
> for len(c) > 0 {
> // there is a newer result available
> result <- c
> }
> // process latest available result
>
> In normal case I don't want to discarding. Even consumer find the channel
> is full, it should not to discard.
>
>
>>
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