If I understand what you're trying to do, I'd approach it this way, using a 
generously buffered channel and discarding the extras at the consumer, as 
shown below, instead of at the producer:

result <- c // wait for result to appear
for len(c) > 0 {
    // there is a newer result available
    result <- c
}
// process latest available result




>

-- 
You received this message because you are subscribed to the Google Groups 
"golang-nuts" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to golang-nuts+unsubscr...@googlegroups.com.
To view this discussion on the web visit 
https://groups.google.com/d/msgid/golang-nuts/e2da4c3a-7b51-4b12-9b15-cc553ea68e0cn%40googlegroups.com.

Reply via email to