Bryan, Use the test case from the question: buffer := "83f982d600c1caca7a6".
https://play.golang.org/p/1gN7Y4ajOH Peter On Monday, November 13, 2017 at 7:42:16 PM UTC-5, Bryan Mills wrote: > > In this case, the "code golf" solution seems clearer: > https://play.golang.org/p/Jxkf2Vheml > > On Monday, November 13, 2017 at 3:57:57 PM UTC-8, peterGo wrote: >> >> Christian, >> >> Your specialized convertCharToInt32 function, which returns []uint32, is >> slow in comparison to a more general HexToUint function. >> >> BenchmarkHexToUint32-8 20000000 88.9 ns/op 16 B/op 2 allocs/op >> BenchmarkCharToInt32-8 3000000 438 ns/op 96 B/op 22 allocs/op >> >> Playground: https://play.golang.org/p/OeUDEV9Xpb >> >> Peter >> >> On Monday, November 13, 2017 at 1:51:21 AM UTC-5, Christian LeMoussel >> wrote: >>> >>> I have a data stream of bytes and I'd like to get array of int32 (from >>> four bytes). >>> >>> func convertCharToInt32(buffer string) []uint32 { >>> const SIZEOF_INT32 = 4 >>> >>> var hh = make([]byte, 2) >>> var cbuffer = make([]byte, len(buffer)/2) >>> var hbuffer = make([]uint32, len(cbuffer)/SIZEOF_INT32) >>> >>> for i := 0; i < 28; i++ { >>> hh[0] = buffer[i*2] >>> hh[1] = buffer[i*2+1] >>> if s, err := strconv.ParseUint(string(hh[:]), 16, 64); err == >>> nil { >>> cbuffer[i] = byte(s) >>> } >>> } >>> >>> for i := range hbuffer { >>> hbuffer[i] = uint32(Endian.Uint32(cbuffer[i*SIZEOF_INT32 : (i+1) >>> *SIZEOF_INT32])) >>> } >>> >>> return hbuffer >>> } >>> >>> buffer := "83f982d600c1caca7a6" >>> hbuffer := convertCharToInt32(buffer) >>> >>> >>> >>> The code above seems to work, but perhaps there is a built-in function >>> in Go that I've missed or there is a super cool hack that does that in one >>> instruction? >>> >>> >>> -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
