In this case, the "code golf" solution seems clearer: https://play.golang.org/p/Jxkf2Vheml
On Monday, November 13, 2017 at 3:57:57 PM UTC-8, peterGo wrote: > > Christian, > > Your specialized convertCharToInt32 function, which returns []uint32, is > slow in comparison to a more general HexToUint function. > > BenchmarkHexToUint32-8 20000000 88.9 ns/op 16 B/op 2 allocs/op > BenchmarkCharToInt32-8 3000000 438 ns/op 96 B/op 22 allocs/op > > Playground: https://play.golang.org/p/OeUDEV9Xpb > > Peter > > On Monday, November 13, 2017 at 1:51:21 AM UTC-5, Christian LeMoussel > wrote: >> >> I have a data stream of bytes and I'd like to get array of int32 (from >> four bytes). >> >> func convertCharToInt32(buffer string) []uint32 { >> const SIZEOF_INT32 = 4 >> >> var hh = make([]byte, 2) >> var cbuffer = make([]byte, len(buffer)/2) >> var hbuffer = make([]uint32, len(cbuffer)/SIZEOF_INT32) >> >> for i := 0; i < 28; i++ { >> hh[0] = buffer[i*2] >> hh[1] = buffer[i*2+1] >> if s, err := strconv.ParseUint(string(hh[:]), 16, 64); err == nil >> { >> cbuffer[i] = byte(s) >> } >> } >> >> for i := range hbuffer { >> hbuffer[i] = uint32(Endian.Uint32(cbuffer[i*SIZEOF_INT32 : (i+1)* >> SIZEOF_INT32])) >> } >> >> return hbuffer >> } >> >> buffer := "83f982d600c1caca7a6" >> hbuffer := convertCharToInt32(buffer) >> >> >> >> The code above seems to work, but perhaps there is a built-in function in >> Go that I've missed or there is a super cool hack that does that in one >> instruction? >> >> >> -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
