Hi Christian, just a form note - it would be preferable and easier for the readers to put a code snippet into https://play.golang.org and share the link, similar to this one: https://play.golang.org/p/p3TNDze923
It also helps to make sure that program is syntactically correct (not clear in your example what "Endian" refers to - binary.LittleEndian?) and the example can be run in the Playground. Take a look at examples and API docs in https://golang.org/pkg/encoding/binary/ - they should cover what the stdlib provides for conversions. On Monday, November 13, 2017 at 7:51:21 AM UTC+1, Christian LeMoussel wrote: > > I have a data stream of bytes and I'd like to get array of int32 (from > four bytes). > > func convertCharToInt32(buffer string) []uint32 { > const SIZEOF_INT32 = 4 > > var hh = make([]byte, 2) > var cbuffer = make([]byte, len(buffer)/2) > var hbuffer = make([]uint32, len(cbuffer)/SIZEOF_INT32) > > for i := 0; i < 28; i++ { > hh[0] = buffer[i*2] > hh[1] = buffer[i*2+1] > if s, err := strconv.ParseUint(string(hh[:]), 16, 64); err == nil > { > cbuffer[i] = byte(s) > } > } > > for i := range hbuffer { > hbuffer[i] = uint32(Endian.Uint32(cbuffer[i*SIZEOF_INT32 : (i+1)* > SIZEOF_INT32])) > } > > return hbuffer > } > > buffer := "83f982d600c1caca7a6" > hbuffer := convertCharToInt32(buffer) > > > > The code above seems to work, but perhaps there is a built-in function in > Go that I've missed or there is a super cool hack that does that in one > instruction? > > > -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
