On 07/26/2012 01:32 PM, Paulo J. Matos wrote: > On 26/07/12 13:27, Richard Guenther wrote: >>> Why would the fill value in a memset call be required to fit in a host char? >> >> Obviously because of the implementation detail of its caller. > > Richard, I am sorry if I was not more clear. I understand that this is > required because the caller uses a pointer to a char to pass the value > of the fill, therefore the fill must fill in a host char. But is there > any reason to introduce this constraint? > > Wouldn't it be more flexible, albeit probably more complex, to pass the > value through a TARGET char or a HOST type as big as a TARGET char?
Probably. I suspect a patch would be welcome. Andrew.
