On 26/07/12 13:27, Richard Guenther wrote:
Why would the fill value in a memset call be required to fit in a host char?
Obviously because of the implementation detail of its caller.
Richard.
Richard, I am sorry if I was not more clear. I understand that this is
required because the caller uses a pointer to a char to pass the value
of the fill, therefore the fill must fill in a host char. But is there
any reason to introduce this constraint?
Wouldn't it be more flexible, albeit probably more complex, to pass the
value through a TARGET char or a HOST type as big as a TARGET char?
Cheers,
--
PMatos
