------- Additional Comments From igodard at pacbell dot net 2005-02-17 04:10 ------- Please:
yes, the int value lwbi arising from the conversion of char(0x80) is the int value 0xffffff80, i.e. int(-128); you are quite right about that. That value is being *subtracted* from the int value upbi arising from the conversion of char(0x7f) which is the value 0x0000007f, i.e. 127. If you subtract -128 from 127, i.e (127 - (-128)), the result is 255, a positive number and there is NO overflow. This is signed subtract and it is permitted to subtract a negative from a positive. The result is exact. The result of the subtract is the positive number int(255). That can be converted to size_t (which is unsigned in in this case) also without overflow. Yet there is still a warning message. If the problem here is not clear, please pass this report on to your other colleagues for a second opinion. Thank you. Ivan -- What |Removed |Added ---------------------------------------------------------------------------- Status|RESOLVED |UNCONFIRMED Resolution|INVALID | http://gcc.gnu.org/bugzilla/show_bug.cgi?id=20019