------- Additional Comments From schlie at comcast dot net 2005-02-17 13:20 ------- (In reply to comment #6) > What should get a warning is the assignment of 0x80 to a char.
Not that either, as although the two differ in sign, the value does not exceed the type's precision. -- http://gcc.gnu.org/bugzilla/show_bug.cgi?id=20019