Ted,
To get an SVD isn't it more common to compute the eigen decomposition of
[ 0 A' ]
[ A 0 ]
Rather than A' A?
Thanks. Never seen that approach but it is mathematically equivalent
indeed. I will try it.
Regards,
Dim.
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Dimitri Pourbaix *
Institut d'Astronomie et d'Astrophysique * Don't worry, be happy
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