On May 14, 2008, at 9:47 AM, "Norbert Gábor Papp" <[EMAIL PROTECTED]
m> wrote:
Thanks for your fast reply,but sorry, I don't really understand
this...
The situation -> both player pass, end of the game, I need the score.
I want to remove dead-stones which means :
if (IsGameEnded) {
for (int i=0, int ,j=0; i<table.sizeX,y<table.sizeZ;i++,j++){
if dead(i,j)
{
table.remove(i,j);
}
}
countterritories();
.
.
.
}
I'm interested in the function dead(), which is true when a stone is
dead after both player pass,and the game is ended.
A proper answer requires knowing what your pass criteria is and
possibly which logic is available. If you pass when your remaining
options are illegal or fill one point eyes, then the logic is
relatively simple 99% of the time... All stones in atari are dead. Ko
messes that up if your opponent passes instead filling a ko.
2008/5/14 Jason House <[EMAIL PROTECTED]>:
That's a function of how smart your bot is. If you play until you
only have eye-filling moves, you can safely assume all of your
opponent's stones are alive, all your groups with two eyes are
alive, and everything else is dead. Note the asymetry - your
opponent may use a different strategy.
If you use random playouts, you could compute the probability of
specific points being owned by each player, and use that for both
passing and marking dead stones.
There are many other variants that use life and death modules, but
I'll assume you don't have them yet
Sent from my iPhone
On May 14, 2008, at 9:10 AM, "Norbert Gábor Papp" <[EMAIL PROTECTED]
m> wrote:
Thanks! How can I identify dead stones?
I haven't seen algorithm for this, and it is a very important part of
a go program
2008/5/14, Don Dailey <[EMAIL PROTECTED]>:
This probably explains it better than I could:
http://senseis.xmp.net/?TrompTaylorRules
- Don
Norbert Gábor Papp wrote:
Hi!
Can you tell me some algorithm to compute the score ? (Both players
pass,
and who is the winner...)
Thanks, Norbert
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