Just to clarify the clarifications, the force will be the area of the
piston minus the area of the rod. The adjuster is pulling the wire/rod.
Neil Schiller
1983 C&C 35-3, #028, "Grace"
Whitehall, Michigan
WLYC
On 6/11/2020 9:01 AM, Joe Della Barba via CnC-List wrote:
If the gauge was specially printed for the size of the piston, it
might actually read tension. If it is just a generic pressure gauge,
tension would be PSI x Area of Piston in Square Inches.
(i.e 1000 PSI on 2 square inches = 2,000 pounds of tension)
Joe Della Barba
Coquina C&C 35 MK I
On 6/11/2020 8:57 AM, Dennis C. via CnC-List wrote:
We had this discussion many years ago on this list.
I think I recall that this is tension (in pounds) on the wire/rod. I
think the reading on a hydraulic back stay adjuster gauge is pressure
(in psi) on the piston. If so, they are not the same.
I think you have to convert the psi reading to tension based on the
area of the piston in YOUR adjuster. For instance, if your piston is
1 1/4 inches in diameter, you would have an area of 1.23 sq inches.
So 1000 psi on the piston would exert 1230 pounds tension on the back
stay.
I could be entirely wrong. Can someone verify this?
Touche's hydraulic back stay gauge is too opaque to read. We adjust
to sail shape and have a batten with green/yellow/ red/black tape
marks for repeating settings.
--
Dennis C.
Touche' 35-1 #83
Mandeville, LA
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