Paul, Thanks for these more accurate "ratings".  It definitely helps to
give an answer to the question of "what does good look like?"  I have never
saught out actual ratings for refrigerator loads and I've never gotten a
AHr meter installed - besides the plethora of variables which make single
point AHr usage almost impossible to  determine.  It seemed like nobody
else had provided a frame of reference besides examples of their own setup
and I was kinda trying to describe a worst case numbers scenario to provide
an upper boundary to the project.  Your numbers bring further clarity by
providing a lower boundary.

You and other listers are absolutely correct that adding insulation is the
best way to reduce refrigerator AHr load.

Thanks,
Josh Muckley
S/V Sea Hawk
1989 C&C 37+
Solomons, MD



On Mon, Oct 16, 2017, 9:20 AM Dreuge via CnC-List <cnc-list@cnc-list.com>
wrote:

>
> If you have a refrigeration load of 120AH/day, don’t waist money on
> increasing battery and charging capacity.
>
> Spend a little cash on better insulation or rebuild your box with more and
> better insulation.   It is not unreasonable to shoot for a refrigeration
> load under 30AH/day.  Just have a look at Wally’s Stella Blue page titled
> “Marine refrigeration and freezer on 22AH/day”(I recall he has a  Frigoboat
> unit with keel cooler).   Technautics claim that their CoolBlue system
> consumes “24AH/Day for a 7 cubic foot fridge/freezer with R-30” and
> “operates at ambient temperatures up to 120F without a loss in system
> efficiency.”   Even the Isotherm claims their ASU SP3751 can achieve loads
> under 20AH/day.   Now making ice or cooling down warm beer on a really hot
> day will likely have higher load demands, but the message is still the
> same.  Insulation is cheaper than batteries and lasts a lot longer too.
>
>
>
> -
> Paul E.
> 1981 C&C 38 Landfall
> S/V Johanna Rose
> Fort Walton Beach, FL
>
> http://svjohannarose.blogspot.com/
>
> On Oct 14, 2017, at 2:02 PM, cnc-list-requ...@cnc-list.com wrote:
>
> Lets consider some hypothetical numbers based on the rep's info.  If a 100w
> panel were %100 effective and operated for 8 hours, you would get 800w-hrs
> of power per day.  800w divided by 12v = 67amp-hrs.  67 divided by 24hrs =
> 2.8amps current draw on average.
>
> That kinda gives you a ball park for what type of loads you'll be facing.
> Round up to 5amps/hr if you like for margin.  5 *24=120AHr per day.
>
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