You need to swap the arguments; "⍺|⍵" in APL is "⍵ mod ⍺" or "⍵ rem ⍺" or "⍵ % ⍺" in most other systems.
On 20 June 2017 at 09:11, Elias Mårtenson <loke...@gmail.com> wrote: > Wolfram Alpha tells me it should be 5J3: > > https://www.wolframalpha.com/input/?i=(5%2B3i)+mod+(14%2B5i) > > Regards, > Elias > > On 20 June 2017 at 16:02, Jay Foad <jay.f...@gmail.com> wrote: > >> With the demo version of APL2 I get: >> >> 5J3 ∣ 14J5 >> ¯4J1 >> 5J3 | 1J4 >> ¯4J1 >> 5J3 | ¯4J1 >> ¯4J1 >> >> Jay. >> >> On 19 June 2017 at 18:03, Frederick Pitts <fred.pit...@comcast.net> >> wrote: >> >>> Jürgen, >>> >>> With gnu apl (svn 961 on Fedora 25, Intel(R) Core(TM) i7-6700 >>> CPU), the residue function (∣) yields the following: >>> >>> 5J3 ∣ 14J5 >>> 1J4 >>> 5J3 | 1J4 >>> ¯4J1 >>> 5J3 | ¯4J1 >>> ¯4J1 >>> The above result means that two elements in the complete residue system >>> (CSR) for mod 5J3 are equal, i.e. 1J4 = ¯4J1 mod 5J3, which is not >>> allowed. None of the elements of a CSR can be equal modulo the CSR's >>> basis. >>> >>> Regards, >>> >>> Fred >>> >>> >> >
