Wolfram Alpha tells me it should be 5J3: https://www.wolframalpha.com/input/?i=(5%2B3i)+mod+(14%2B5i)
Regards, Elias On 20 June 2017 at 16:02, Jay Foad <jay.f...@gmail.com> wrote: > With the demo version of APL2 I get: > > 5J3 ∣ 14J5 > ¯4J1 > 5J3 | 1J4 > ¯4J1 > 5J3 | ¯4J1 > ¯4J1 > > Jay. > > On 19 June 2017 at 18:03, Frederick Pitts <fred.pit...@comcast.net> wrote: > >> Jürgen, >> >> With gnu apl (svn 961 on Fedora 25, Intel(R) Core(TM) i7-6700 >> CPU), the residue function (∣) yields the following: >> >> 5J3 ∣ 14J5 >> 1J4 >> 5J3 | 1J4 >> ¯4J1 >> 5J3 | ¯4J1 >> ¯4J1 >> The above result means that two elements in the complete residue system >> (CSR) for mod 5J3 are equal, i.e. 1J4 = ¯4J1 mod 5J3, which is not >> allowed. None of the elements of a CSR can be equal modulo the CSR's >> basis. >> >> Regards, >> >> Fred >> >> >
